Answer:
correct answer is d)
Explanation:
This answer demonstrates law of conservation of mass because the mass of the products is equal to the mass of reactants with the help of the coefficients which is the process known as balancing. This answer also includes the correct formulas, as Br is a gas so it MUST be written as Br2. hope this helps:)
Answer:
2.268 L
Explanation:
According to Ideal Gas Law, " The Volume of a given mass of gas is inversely proportional to the applied Pressure and directly proportional to applied temperature, ". Mathematically the initial and final states of gas are given as,
P₁ V₁ / T₁ = P₂ V₂ / T₂ ----------- (1)
Data Given;
P₁ = 0.998 atm
V₁ = 2.1 L
T₁ = 36 °C = 309 K
P₂ = 0.90 atm
T₂ = 28 °C = 301 K
V₂ = ??
Solving equation 1 for P₂,
V₂ = P₁ V₁ T₂ / T₁ P₂
Putting values,
V₂ = (0.998 atm × 2.1 L × 301 K) ÷ (309 K × 0.90 atm)
V₂ = 2.268 L
Answer:
Because it is too dense for that to happen
Explanation:
Answer : The percentage aniline protonated is, 0.0209 %
Explanation :
First we have to calculate the pOH.

Now we have to calculate the hydroxide ion concentration.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![5.68=-\log [OH^-]](https://tex.z-dn.net/?f=5.68%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=2.09\times 10^{-6}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D2.09%5Ctimes%2010%5E%7B-6%7DM)
The equilibrium chemical reaction will be:

From the reaction we conclude that,
Concentration of
ion = Concentration of
ion = 
Now we have to calculate the percentage aniline protonated.


Thus, the percentage aniline protonated is, 0.0209 %
<em>Answer:</em>
- 0.052301 km have 5 significant figure
- 400 cm have 1 significant figure
- 50.0 m have 3 significant figure
- 4500.01 ml have 6 significant figure
<em>Explanation:</em>
According to rules of significant figure
0.052301 km have 5 significant figure:
- Zero to the left of the first non zero digit not significant.
- Zero between the non zero digits are significant.
<em>400 cm have 1 significant figure:</em>
- Trailing zeros are not significant in numbers without decimal points.
<em>50.0 m have 3 significant figure:</em>
- Trailing zeros are significant in numbers when there is decimal points.
<em>4500.01 ml have 6 significant figure:</em>
- Zero between the non zero digits are significant.