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mel-nik [20]
2 years ago
6

Identify which of these molecules has the highest boiling point and give the reasoning why in terms of intermolecular force. CHC

I3,CH3COOH, CO2
Chemistry
1 answer:
PolarNik [594]2 years ago
7 0

Answer:

CH3COOH

Explanation:

CH3COOH has the highest boiling point because it participates in the strongest intermolecular interactions. The -OH group can participate in hydrogen bonding with other -OH groups. Hydrogen bonds are very strong because they are the result of large partial positive charge on the hydrogen and large partial negative charge on the oxygen. When surrounded by other -OH groups, the partial positive charge on the hydrogen can form temporary bonds with the partial negative charge of an oxygen on another molecule. The stronger the intermolecular interactions, the more difficult they are to overcome, thus increasing the boiling point.

The strongest IMF the other molecules participate in are dipole-dipole. These interactions are not as strong as hydrogen bonding.

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How is a mixture such as a plate of pasta different from a mixture such as air
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Identify the correct lewis structure for the following ionic compound. SrO
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Question 26 Suppose a flask is filled with of and of . The following reaction becomes possible: The equilibrium constant for thi
Blizzard [7]

Answer:

0.36 M

Explanation:

There is some info missing. I think this is the complete question.

<em>Suppose a 250 mL flask is filled with 0.30 mol of N₂ and 0.70 mol of NO. The following reaction becomes possible: </em>

<em>N₂(g) +O₂(g) ⇄ 2 NO(g) </em>

<em>The equilibrium constant K for this reaction is 7.70 at the temperature of the flask.  Calculate the equilibrium molarity of O₂. Round your answer to two decimal places.</em>

<em />

Initially, there is no O₂, so the reaction can only proceed to the left to attain equilibrium. The initial concentrations of the other substances are:

[N₂] = 0.30 mol / 0.250 L = 1.2 M

[NO] = 0.70 mol / 0.250 L = 2.8 M

We can find the concentrations at equilibrium using an ICE Chart. We recognize 3 stages (Initial, Change, and Equilibrium) and complete each row with the concentration or change in the concentration.

    N₂(g) +O₂(g) ⇄ 2 NO(g)

I    1.2        0              2.8

C  +x         +x            -2x

E  1.2+x      x           2.8 - 2x

The equilibrium constant (K) is:

K=7.70=\frac{[NO]^{2}}{[N_{2}][O_{2}]} =\frac{(2.8-2x)^{2} }{(1.2+x).x}

Solving for x, the positive one is x = 0.3601 M

[O₂] = 0.3601 M ≈ 0.36 M

7 0
3 years ago
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