B4 the tackle:
<span>The linebacker's momentum = 115 x 8.5 = 977.5 kg m/s north </span>
<span>and the halfback's momentum = 89 x 6.7 = 596.3 kg m/s east </span>
<span>After the tackle they move together with a momentum equal to the vector sum of their separate momentums b4 the tackle </span>
<span>The vector triangle is right angled: </span>
<span>magnitude of final momentum = √(977.5² + 596.3²) = 1145.034 kg m/s </span>
<span>so (115 + 89)v(f) = 1145.034 ←←[b/c p = mv] </span>
<span>v(f) = 5.6 m/s (to 2 sig figs) </span>
<span>direction of v(f) is the same as the direction of the final momentum </span>
<span>so direction of v(f) = arctan (596.3 / 977.5) = N 31° E (to 2 sig figs) </span>
<span>so the velocity of the two players after the tackle is 5.6 m/s in the direction N 31° E </span>
<span>btw ... The direction can be given heaps of different ways ... N 31° E is probably the easiest way to express it when using the vector triangle to find it</span>
I’m assuming it is kinetic energy. When velocity increases there is acceleration therefore it’s moving which then means it has kinetic energy
Answer:
it takes the car 4.362 seconds to cover the distance of 88.4 m.
Explanation:
The distance the car covers is given by the function
,
where , and , putting these in we get:
Now, when the car has moved to 88.4m, , or
which is a quadratic equation with solutions
We take the first solution , <em>since at that time the car is still moving right and decelerating</em>. The second solution describes the situation where the car has stopped decelerating and is now moving leftwards because the decelerating is leftwards, <em>which is utterly wrong because we know that cars do not start moving backwards after the brakes have stopped them! </em>
Thus, it takes the car 4.362 seconds to cover the distance of 88.4 m.
Answer:
15.666666666667 gram/cubic centimeter
Answer:
1) A:1, B:1, C:1
2) A:1, B:1, C:1
3) B:1, C:2, A:3
Explanation:
1)
a = , where V - linear speed.
R - radius of ferris wheel.
These values are constant, so at any position centripetal acceleration will be the same.
2)
F = ma = , where a - centripetal acceleration.
V - linear speed.
R - radius of ferris wheel.
These values are constant, so at any position centripetal force will be the same.
3)
So, at bottom point normal force is maximume, at top point normal force is minimum.
B:1, C:2, A:3 (bottom: Greatest, midheight: Second greatest, top: Third greatest)