Answer:
The angular velocity of the wheel in terms of d, F, and I is, ω = d/t (F/I α) s⁻¹
Explanation:
Given,
The angular velocity ω
The displacement d
The magnitude of the applied force, F
The moment of inertia of the wheel I = mr²
The angular velocity can be written as
ω = v /r
where,
v - linear velocity
r - radius of the wheel
ω = d/t (1/r) (∵ v = d /t)
The force can be written as,
F = m a
= m α r (∵ a = α r)
Multiplying both sides by r
F r = m r² α
F r = I α (∵ I = mr²)
r = I α / F
Substituting in the above equation for ω
ω = d/t (F/I α) s⁻¹
Hence, the angular velocity of the wheel in terms of d, F, and I is, ω = d/t (F/I α) s⁻¹
It is 72 km/h
I hope it helps
answer - d
set up equation
the velocity can be found through the change in kinetic energy
due to the conversation of energy, the change in kinetic energy is the same as the change in potential energy when the height is changed
ΔK =
ΔU = mgΔh
ΔK = ΔU
= mgΔh
= 2gΔh
v =
values
g = 9.8
Δh = 42 - 4.2 = 37.8 m
plug in values
v =
v =
v = 27.2
answer choice D