Answer: W =
J
Explanation: Since the potassium ion is at the outside membrane of a cell and the potential here is lower than the potential inside the cell, the transport will need work to happen.
The work to transport an ion from a lower potential side to a higher potential side is calculated by

q is charge;
ΔV is the potential difference;
Potassium ion has +1 charge, which means:
p =
C
To determine work in joules, potential has to be in Volts, so:

Then, work is


To move a potassium ion from the exterior to the interior of the cell, it is required
J of energy.
If you take 50 meters and divide by 23.1 seconds, you will get 2.16 meters per second.
So his average speed is 2.16 m/s.
false. clinical deals with patients and treats the.
research looks at root causes which clinical applies
Answer:
Potential difference = 6.0 V
I for 1.0Ω = 6 A
I for 2.0Ω = 3 A
I for 3.0Ω = 2 A
Explanation:
Potential difference (ΔV) = Current (I) x Resistance (R)
The potential difference is constant and equals 6.0 V, hence;
I = ΔV/R
When R = 1.0, I =6/1 = 6 amperes
When R = 2.0, I = 6/2 = 3 amperes
When R = 3.0, I = 6/3 = 2 amperes
<em>The potential difference is 6.0 V and the current is 6, 3, and 2 amperes for a resistance of 1.0, 2.0 and 3.0Ω respectively.</em>