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grigory [225]
3 years ago
7

An egg hits the ground with an impulse of 67 Ns and a force of 257 N. What was the amount of

Physics
1 answer:
FromTheMoon [43]3 years ago
8 0

Answer:

0.26seconds

Explanation:

Impulse is the product of force and time

Impulse =Force * Time

Given

Impulse = 67Ns

Force = 257N

Required

Time

From the formula;

Time = Impulse/Force

Time = 67/257

Time = 0.26s

Hence the amount of time is 0.26seconds

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If a calorie is equivalent to 4.184 joules how many joules are contained in 250 kg calories slice of pizza
Andreyy89
In order to answer this, we will set up a simple ratio as such:

1 calorie = 4.184 joules

1 kilocalorie = 1000 calories

1 kilocalorie = 4,184 joules

250 kilocalories = x joules

Cross multiplying the second and third equations, we get:

x joules = 4,184 * 250

250 kilocalories are equivalent to 1,046 kJ
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3 years ago
17. Suppose you were standing on a scale in an elevator in free fall. What would the scale read?
lianna [129]

17

What would the scale read? zero

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4 years ago
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Newton’s Second Law of motion defines force in terms of mass and acceleration, F= ma. Which of the following is false? The term
NikAS [45]

Answer:

The forces creating the net force must lie in the same direction.

Explanation:

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If there are several forces acting on the body in different directions, then we have to find teh net force by using the vector sum and then find the acceleration.

It is not necessary that all the forces acting in the same direction.

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5 0
4 years ago
D section a only still need help on this
SIZIF [17.4K]

Acceleration means speeding up, slowing down, or changing direction. The graph doesn't show anything about direction, so we just have to examine it for speeding up or slowing down ... any change of speed.

The y-axis of this graph IS speed. So the height of a point on the line is speed. If the line is going up or down, then speed is changing.

Sections a, c, and d are all going up or down. Section b is the only one where speed is not changing. So we can't be sure about b, because we don't know if the track may be curving ... the graph can't tell us that. But a, c, and d are DEFINITELY showing acceleration.

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4 years ago
A(n) 0.2 kg object is swung in a vertical circular path on a string 0.1 m long. The acceleration of gravity is 9.8 m/s2 . If a c
Leya [2.2K]

Answer:

T=83.37N

Explanation:

Since the object is under a circular motion, according to Newton's second law, when the object is at the top of the circle we have:

\sum F_y: T-mg=F_c

Where F_c is the centripetal force and is given by:

F_c=ma_c=m\frac{v^2}{r}

Replacing and solving for T:

T=m\frac{v^2}{r}+mg\\T=0.2kg\frac{(6.38\frac{m}{s})^2}{0.1m}+0.2kg(9.8\frac{m}{s^2})\\T=83.37N

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4 years ago
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