N-y=4y-n/m Forst we take care of the formula! I did it this way 4y-n/m=n-y 4y-n-n=-ym 4y-2n=-ym -2n=-ym/4y Now we just replace y with 3 and m with 7 -2n=-3*7/4*3 -2n=-21/12 n=-22/12/2 n=-22/6 I think this is it
Solution Let E1 be the event that coin 1 is selected and E2 the event that coin 2 is selected. Let F be the event that exactly 7 of the 10 flips lands on heads, let G be the event that the fist flip is heads.