All categories

1 year ago

The theater sells two types of tickets: adult tickets for $6 and child tickets for $4.

Mathematics

1 answer:

andrey2020 [161]1 year ago

4 0

Answer:

237

Step-by-step explanation:

This is a system of equations.

The theater sold 364 adult and child tickets, so a + c = 364

They made a total of $1930. Each adult ticket was $6 & child tickets were $4. The second equation is 6a + 4c = 1930.

Let's line them up

a + c = 364

6a + 4c = 1930

Since we need to solve for the number of adult tickets, we want to get rid of the c variable. I'm going to multiply the entire first equation by -4 to do this. The second equation stays the same. Now, I have:

-4a - 4c = -1456

6a + 4c = 1930 Add them together

----------------------

2a = 474 Divide by 2 to solve for a

a = 237

There were 237 adult tickets sold

You might be interested in

9 pencils cost $7.74 Which equation would help determine the cost of 6 pencils?

Stells [14]

Answer $5.16

Step-by-step explanation:

$7.74 divided by 9 is 0.86 so 0.86 per pencil mutiply that by 6 because you have six pencils and you get 5.16 for six pencils

5 0

3 years ago

Read 2 more answers

Can someone please help I will give brainliest and please if you don’t know the answer don’t put anything due at 12:00

hjlf

Answer:

Answer: (7,-2)

Step-by-step explanation:

Look at the formula

1) (x – h)^2 + (y – k)^2 = r2

the center is described by (h,k)

now look at

(x – 7)^2 + (y +2)^2 = 25

here h=7

but k= -2 because is (y+2) =(y-(-2))

4 0

3 years ago

Evaluate the expression for the given value of the variable. n=500 ∛n/4+n/10=?

schepotkina [342]

Answer:

Step-by-step explanation:

To solve the expression, $\sqrt[3]{\frac{n}{4}} + \frac{n}{10}$ substitute n = 500 and simplify according to order of operations.

$\sqrt[3]{\frac{500}{4} } + \frac{500}{10}\\\\\sqrt[3]{125}+50\\ 5+50\\\\55$

4 0

3 years ago

Multiply the following 1)34/7×3 2)3/8×7 3)3/4×7

Gelneren [198K]

Answer:

1) 102/21

2) 21/51

3) 21/24

Step-by-step explanation:

7 0

3 years ago

Solve for y. y y —— = —— P-9 P+9

Veronika [31]

9514 1404 393

Answer:

y = 0

Step-by-step explanation:

Subtracting the right side gives ...

$\dfrac{y}{P-9}-\dfrac{y}{P+9}=0\\\\y\left(\dfrac{(P+9)-(P-9)}{P^2-81}\right)=0\\\\y\left(\dfrac{18}{P^2-81}\right)=0\\\\\boxed{y=0}$

The factor multiplying y cannot be zero, so y must be zero.

5 0

3 years ago