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Vesna [10]
3 years ago
6

Which integral gives the area of the region in the first quadrant bounded by the graphs of y^2 = x − 1, x = 0, y = 0, and y = 2?

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
5 0
Weird that the only choices are given as integrals with respect to x. (Integration along the y axis would be way easier, but whatever)

The fourth option should do it.
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4 years ago
Please help me on this question
serious [3.7K]

Answer:

The answer is A

Step-by-step explanation:

\frac{1 \times 3}{2 \times 3}  =  \frac{3}{6}  \\  \\  \frac{2 \times 2}{3 \times 2}  =  \frac{4}{6}

5 0
3 years ago
find the middle integer if the sum of the greatest and the least of the three consecutive integers is 82
allsm [11]
 <span>x= greatest 
x+2= least 

x + x + 2 = 82 

2x + 2 = 82 
-2 -2 

2x = 80 
---- ----- 
2 2 

x=40 

Check: 
x=40 
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x+1=40+1=41 
the middle integer is 41</span>
6 0
3 years ago
What is (−7)(−2)+(−15÷3)
vovangra [49]
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so you have 14+(-5) which is just 14-5

it gives you 9
3 0
3 years ago
PLS ANSWER IF GOTTEN RIGHT WILL MARK BRAINLIEST
Mandarinka [93]
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