The number of hours of daylight, H, on day t of any given year (on January 1, tequals1) in a particular city can be modeled
by the function H(t)equals13 plus 8.2 sine [StartFraction 2 pi Over 365 EndFraction (t minus 77 )]. a. March 18, the 77th day of the year, is the spring equinox. Find the number of hours of daylight in the city on this day. b. June 18, the 169th day of the year, is the summer solstice, the day with the maximum number of hours of daylight. Find the number of hours of daylight in the city on this day. c. December 18, the 352nd day of the year, is the winter solstice, the day with the minimum number of hours of daylight. Find the number of hours of daylight in the city on this day.
1 answer:
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Solution:
x y ║ z w→→Given
Also, x z is a transversal, that intercepts x y and z w.
So, ∠ x z w=∠z x y→→Alternate interior angles as, x y ║ z w.
Also, v is point of intersection of x z and y w.
∠ x v y ≅ ∠ z v w→→[ Vertically opposite angles]
So,→→ Δ x y v ~ Δ z w v⇒⇒[Angle-Angle Similarity]
