The number of hours of daylight, H, on day t of any given year (on January 1, tequals1) in a particular city can be modeled
by the function H(t)equals13 plus 8.2 sine [StartFraction 2 pi Over 365 EndFraction (t minus 77 )]. a. March 18, the 77th day of the year, is the spring equinox. Find the number of hours of daylight in the city on this day. b. June 18, the 169th day of the year, is the summer solstice, the day with the maximum number of hours of daylight. Find the number of hours of daylight in the city on this day. c. December 18, the 352nd day of the year, is the winter solstice, the day with the minimum number of hours of daylight. Find the number of hours of daylight in the city on this day.
1 answer:
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<u>Answer:</u>
<u>For a:</u> The probability of getting a red or blue ball is 0.48
<u>For b:</u> The probability of getting a white, blue or orange ball is 0.81
<u>For c:</u> The probability of getting neither white or orange ball is 0.48
<u>Step-by-step explanation:</u>
Probability is defined as the extent to which an event is likely to occurs. It is measured by the ratio of the favorable outcomes to the total number of possible outcomes.
.......(1)
We are given:
Number of red balls in a box = 12
Number of white balls in a box = 18
Number of blue balls in a box = 19
Number of orange balls in a box = 15
Total balls in a box = [12 + 18 + 19 + 15] = 64
- <u>For a:</u>
Number of favorable outcomes (ball must be red or blue) = [12 + 19] = 31
Total number of outcomes = 64
Putting values in equation 1, we get:
- <u>For b:</u>
Number of favorable outcomes (ball must be white or blue or orange) = [18 + 19 + 15] = 52
Total number of outcomes = 64
Putting values in equation 1, we get:
- <u>For c:</u>
Number of favorable outcomes (ball must be white or orange) = [18 + 15] = 33
Total number of outcomes = 64
Putting values in equation 1, we get:
Probability of getting a ball which is neither white or orange = [1 - (Probability of getting a white or orange ball)] = [1 - 0.52] = 0.48