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bulgar [2K]
3 years ago
9

You spin the spinner shown. A spinner is divided into 8 equal regions. Each region is labeled with a numeral from 1 to 8. How ma

ny possible outcomes are there? There are possible outcomes.
Mathematics
1 answer:
Anastasy [175]3 years ago
8 0

Answer:

Therefore,

There are 8 possible outcomes.

Step-by-step explanation:

Given:

A spinner is divided into 8 equal regions.

While Spinner spins it can stop at

Numeral 1 or

Numeral 2 or

Numeral 3 or

Numeral 4 or

Numeral 5 or

Numeral 6 or

Numeral 7 or

Numeral 8 or

So in All, there are 8 Possible outcomes Also Known as Sample Space

Sample Space:

Total number of favorable outcomes.

Denote by "S"

S = { 1 , 2 , 3 , 4 ,5 , 6, 7 ,  8 }

Possible outcomes = n(S) = 8

Therefore,

There are 8 possible outcomes.

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Làm ơn hãy giúp tôi <br> (a+b)²<br> (a-b)²
marysya [2.9K]

Answer:

(a + b) ^{2}  =  {a}^{2}  + 2ab +  {b}^{2}  \\ (a - b) ^{2}  =  {a {}^{2}  - 2ab +  {b}}^{2}

Step-by-step explanation:

hopethe answer helped you :)

8 0
2 years ago
Read 2 more answers
Abby, Bernardo, Carl, and Debra play a game in which each of them starts with four coins. The game consists of four rounds. In e
Sedaia [141]

The probability that, at the tip of the fourth round, each of the players has four coins is 5/192.

Given that game consists of 4 rounds and every round, four balls are placed in an urn one green, one red, and two white.

It amounts to filling in an exceedingly 4×4 matrix. Columns C₁-C₄ are random draws each round; row of every player.

Also, let \%R_{A} be the quantity of nonzero elements in R_{A}.

Let C_{1}=\left(\begin{array}{l}1\\ -1\\ 0\\ 0\end{array}\right).

Parity demands that \%R_{A} and\%R_{B} must equal 2 or 4.

Case 1: \%R_{A}=4 and \%R_B=4. There are \left(\begin{array}{l}3\\ 2\end{array}\right)=3 ways to put 2-1's in R_A, so there are 3 ways.

Case 2: \%R_{A}=2 and \%R_B=4. There are 3 ways to position the -1 in R_A, 2 ways to put the remaining -1 in R_B (just don't put it under the -1 on top of it!), and a pair of ways for one among the opposite two players to draw the green ball. (We know it's green because Bernardo drew the red one.) we are able to just double to hide the case of \%R_{A}=4,\%R_{B}=2 for a complete of 24 ways.

Case 3: \%R_A=\%R_B=2. There are 3 ways to put the -1 in R_{A}. Now, there are two cases on what happens next.

  • The 1 in R_B goes directly under the -1 inR_A. There's obviously 1 way for that to happen. Then, there are 2 ways to permute the 2 pairs of 1,-1 in R_C andR_D. (Either the 1 comes first inR_C or the 1 comes first in R_D.)
  • The 1 in R_B doesn't go directly under the -1 in R_A. There are 2 ways to put the 1, and a couple of ways to try and do the identical permutation as within the above case.

Hence, there are 3(2+2×2)=18 ways for this case. There's a grand total of 45 ways for this to happen, together with 12³ total cases. The probability we're soliciting for is thus 45/(12³)=5/192

Hence, at the top of the fourth round, each of the players has four coins probability is 5/192.

Learn more about probability and combination is brainly.com/question/3435109

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3 0
2 years ago
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Need help asap for test
alex41 [277]

Answer:

a=4 and b=-1

Step-by-step explanation:

2(4)+3(-1)= 5

6 0
3 years ago
The equation below describes a parabola. If a is negative, which way does the parabola open? x = ay2
Anastasy [175]
This type of parabola opens either to the left or to the right. The negative makes it open to the left.
8 0
3 years ago
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Which choice is equivalent to the expression below?
Ivan

Answer:

D

Step-by-step explanation:

.......................

3 0
3 years ago
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