it takes 5 seconds to reach a height of 40 ft. and It takes 2.5 seconds to reach maximum height.
Let h(t) represent the height of the ball at time t.
Given that the height is given by:
h(t) = -16t² + 80t + 40
1) For the ball to reach a height 0f 40 ft, h(t) = 40, hence:
40 = -16t² + 80t + 40
16t² - 80t = 0
t(t - 5) = 0
t = 0 or t = 5
Hence it takes 5 seconds to reach a height of 40 ft.
2) The maximum height is at h'(t) = 0,
h'(t) = -32t + 80
-32t + 80 = 0
32t = 80
t = 2.5
It takes 2.5 seconds to reach maximum height.
Find out more at: brainly.com/question/11535666
The 3 option
(3,9), (-7,1), (6,12), (-3, -9)
first, you would rearrange the equation so that like terms were next to each other.
7y - 5y - x2 + 2x2 +3x - 17x
then you would reduce the equation based on like terms
2y + x2 - 14x
then simply rearrange the equation to get the answer, which is <u>B</u>
Answer:
A. =4x3+9x2−25x+12
Step-by-step explanation:
(x+4)(4x−3)(x−1)
=((x+4)(4x−3))(x+−1)
=((x+4)(4x−3))(x)+((x+4)(4x−3))(−1)
=4x3+13x2−12x−4x2−13x+12
=4x3+9x2−25x+12
