When x = 1, y = (5 - 3) / -2 = -1 , let x1 = 1 and y1 = -1
2y = 3x - 5
so slope = 3/2
y - y1 = m(x - x1)
y -(-1) = (3/2)(x - 1)
y + 1 = 3/2 ( x - 1) <----- answer
Answer:
True
Step-by-step explanation:
The definition of the function is a relation with exactly one x for each y. x is the domain, and y is the range, so all functions have a domain and a range.
Answer:
Ф = 
Step-by-step explanation:
It is a bit difficult to input the work here, so I uploaded an image
- First we can use the trig identities to change sec²(Ф) to tan²(Ф) + 1
- Then we can combine like terms
- Then we can factor this as a polynomial function
- Then we can set each term equal to zero and solve for Ф
- The first term tan(Ф) - 2 = 0 has no solution because tan(Ф) ≠ -2 anywhere
- The second term tan(Ф) - 1 = 0 has two solutions of
and 
so these are the solutions to the problem
<em>i dont now sorry find someone else
</em>
Step-by-step explanation:
Mean of the origibal set = 20
No. of terms = 10
Sum = Mean x No. of terms
= 20 x 10 = 200
The sum of additional numbers to make the new set of observstion is 4 + 8 + 12...... + 40 = 220
New Sum = 200 + 220 = 420
The no of terms stay the same
New Mean = New Sum/ N
= 420/10
= 42
