Question

Two buses leave towns 339 miles apart at the same time and travel toward each other. One bus travels 13 mi/h slower than the other. If they meet in 3 hours, what is the rate of each bus?

Answer 1

Answer:

Step-by-step explanation:

Let  x  m/h be the speed of first bus.

Then speed of second bus=x-13 m/h

fist covers covers distance=3x

second covers the distance=3(x-13)=3x-39

again 3x+(3x-39)=339

6x=339+39=378

x=378/6=63

so speed of first bus=63 m/h

speed  of second bus=63-13=50 m/h