How would you write the equation with a slope of 2/3 and a y-intercept of (0,-3)?
1 answer:
Answer:
y = (2/3)x - 3
Step-by-step explanation:
Slope-intercept form: y = mx + b
Note that:
y = (x , y)
m = slope
x = (x , y)
b = y-intercept.
The point is given to you. Note that:
(x , y) = (0 , -3) ∴
x = 0
y = -3
The slope = m = 2/3
Plug in the corresponding numbers to the corresponding variable:
y = mx + b
-3 = (2/3)(0) + b
-3 = 0 + b
b = -3
Plug in -3 for b in the equation:
y = mx + b
y = (2/3)x -3
y = (2/3)x - 3 is your equation.
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