The main point which will immediately make it clear is that you have to plug in 2 for x so that you can find the linit. So, using this simple method you will get the <span>-1/4 answer. Hope you will agree with me and find this useful! Regards.</span>
The expected value per game is -0.26. Over 1000 games, you can expect to lose $263.16.
To find the expected value, we multiply the probability of winning by the amount of winnings, the probability of losing by the amount of loss, and adding those together.
We have a 1/38 chance of winning; 1/38(175) = $4.61. We also have a 37/38 chance of losing; 37/38(5) = $4.87.
$4.61-$4.87 = -$0.26 (rounded)
To five decimal places, our answer is -0.26136; multiplied by 1000 games, this is $261.36 lost.
Let`s say that the expression is written in the form:a * 10^k.4 * 10^3 + 4 * 10^2 = = 4 * 10 * 10^2 + 4 * 10^2 = = 40 * 10^2 + 4 * 10^2 = = 44 * 10^2 = 4.4 * 10^3.Answer:a = 4.4 and k = 3 and the expression in the scientific notation is:4.4 * 10^3.
You don't even have to look up the definition of 'standard deviation'. You only
have to remember that 'smaller standard deviation' means 'less spread-out'.
First, let's find the mean (average). It's not supposed to change:
1/7th of (65 + 71 + 77 + 80 + 82 + 90 + 96) = 561/7 = <u>80 and 1/7</u> .
Now, just pick 7 scores that total 561 and are all bunched up.
The easiest way would be 80, 80, 80, 80, 80, 80, 81 .
But that's so easy that it feels like cheating.
Let's say <u>77, 78, 79, 80, 81, 82, and 84</u> .
