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Bumek [7]
3 years ago
8

Is "What is the area of the floor in this classroom?" a statistical question?

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
6 0

The answer is No

Explanation:

All statistical questions involve collecting numerical data (usually from a group of people) and then analyzing it to draw conclusions about the opinions of people of a certain phenomenon as the data varies depending on the response of each person. This process is not required to determine the area of the floor because this has a unique answer and can simply be found by measuring the height and width of the classroom and then multiplying both numbers. Also, this does not imply gathering a lot of data and the data does not vary.

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Every Sunday John goes to church from his home . He move 2 miles east. How much distance is between home and church
GREYUIT [131]

Answer:

2 miles

Step-by-step explanation:

Because I said so

8 0
3 years ago
On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

7 0
3 years ago
Read 2 more answers
Which equations represent functions? 2x+3y=10. 4x=16. 2x - 3 =14. 3y=18. 14.6=2x
Vlad [161]
2x + 3y = 10 -> y = -2/3x + 10/3 it's a function

4x = 16 -> x =4 it's not a function

2x - 3 = 14 -> x = 8.5 it's not a function

3y = 18 -> y = 6 it's a function

2x = 6 -> x = 3 it's not a function
8 0
3 years ago
Explain why the product of 2 times any number is an even number
leonid [27]

If you add 2 odd numbers together eg. 5+5 it would become an even number eg. 10.

If you add 2 even numbers together eg. 60+60 it would stay as an even number eg.120.

The product is basically the same thing as that but instead of adding the same number twice, you multiplying the number with 2 which is the same as adding two of the same numbers.

7 0
2 years ago
Find the missing exponent. Set up an equation and solve. : x^4·x^n = x^5
algol [13]
Remember
(x^m)(x^n)=x^(m+n)
and
if a^m=a^n, where a=a then n=m


(x^4)(x^n)=x^5
(x^4)(x^n)=x^(4+n)
x^(4+n)=x^5
therefor
4+n=5
minus 4
n=1
5 0
3 years ago
Read 2 more answers
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