Answer:
- Total number of cars having no defection
- Total number of cars out of 560 will have defects =
Step-by-step explanation:
As
- A car factory checks 320 cars, and
Total number of cars = 560
The number of cars defected out of the cars that have
been checked = 
The equation of the scenario will be:
![\left[560\:\times \:308\right]\:\div \:320](https://tex.z-dn.net/?f=%5Cleft%5B560%5C%3A%5Ctimes%20%5C%3A308%5Cright%5D%5C%3A%5Cdiv%20%5C%3A320)
⇒ 
so
- Total number of cars having no defection
- Total number of cars out of 560 will have defects =
2 + 2 - 1 + 1267788 - 100
Using BODMAS (Order of operations);
We add first:
2 + 2 + 1267788 = 1267792
Secondly we subtract:
-1 - 100 = -101
Finally add the two answers:
1267792 + -101 = 1267691
Answer:
Answer below in picture:-
Hope it helps.
Answer:
15°
brainlest
Step-by-step explanation:
Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)
The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.
Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°. Angle PQC has the same measure as angle RQC, so is 15°.
Angle PQC is 15°.
Answer:
13
Step-by-step explanation:
Hope this helps.
