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3 years ago

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Make a He atom with a mass of 4. How many protons did you put in the nucleus?

2 answers:

VLD [36.1K]3 years ago

6 0

Answer:

<em>1.) Make a He atom with a mass of 4. How many protons did you put in the nucleus?</em>

<u>2</u>

<em>2.) Make a Li atom with a mass number of 7. How many electrons did you place in the outermost orbital (ring)?</em>

<u>1</u>

<em>3.) Make a N atom with a mass number of 14. How many neutrons are in the nucleus?</em>

<u>7</u>

<em>4.) Make a B atom with a mass number of 11. How many electrons did you put in the second orbital (ring)?</em>

<u>3</u>

Explanation:

<em>Did it on Edgenuity and got it correct (2020).</em>

FrozenT [24]3 years ago

5 0

Answer:

He has two protons

Li electron has one electron in its outermost orbital.

Number of neutrons of nitrogen = seven neutrons

The second shell of boron: 3 electrons.

Explanation:

An atom is composed of electrons, protons and neutrons. The number of neutrons is determined by subtraction of the atomic number from the mass number.

The electronic configuration is already known for each of atoms in these questions according to standard tables.

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How are some mutations similar? Provide examples.

Hatshy [7]

Answer:

Mutations can be caused by high-energy sources such as radiation or by chemicals in the environment. They can also appear spontaneously during the replication of DNA. Mutations generally fall into two types: point mutations and chromosomal aberrations. In point mutations, one base pair is changed. A single mutation can have a large effect, but in many cases, evolutionary change is based on the accumulation of many mutations with small effects. Mutational effects can be beneficial, harmful, or neutral, depending on their context or location. Most non-neutral mutations are deleterious.

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2 years ago

Read 2 more answers

Use the Nernst equation to calculate the corresponding voltage if the

spayn [35]

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2 years ago

Manganese commonly occurs in nature as a mineral. The extraction of manganese from the carbonite mineral rhodochrosite, involves

hjlf

This is an incomplete question, here is a complete question.

Manganese commonly occurs in nature as a mineral. The extraction of manganese from the carbonite mineral rhodochrosite, involves a two-step process. In the first step, manganese (II) carbonate and oxygen react to form manganese (IV) oxide and carbon dioxide:

$2MnCO_3(s)+O_2(g)\rightarrow 2MnO_2(s)+2CO_2(g)$

In the second step, manganese (IV) oxide and aluminum react to form manganese and aluminum oxide:

$3MnO_2(s)+4Al(s)\rightarrow 3Mn(s)+2Al_2O_3(s)$

Write the net chemical equation for the production of manganese from manganese (II) carbonate, oxygen and aluminum. Be sure your equation is balanced.

Answer : The net chemical equation for the production of manganese is:

$6MnCO_3(s)+3O_2(g)+8Al(s)\rightarrow 6CO_2(g)+6Mn(s)+4Al_2O_3(s)$

Explanation :

The given two chemical reactions are:

(1) $2MnCO_3(s)+O_2(g)\rightarrow 2MnO_2(s)+2CO_2(g)$

(2) $3MnO_2(s)+4Al(s)\rightarrow 3Mn(s)+2Al_2O_3(s)$

First we are multiplying reaction 1 by 3, and reaction 2 by 2, we get:

(1)

(2) $6MnO_2(s)+8Al(s)\rightarrow 6Mn(s)+4Al_2O_3(s)$

Now we are adding both the reactions, we get the overall chemical reaction.

$6MnCO_3(s)+3O_2(g)+6MnO_2(s)+8Al(s)\rightarrow 6MnO_2(s)+6CO_2(g)+6Mn(s)+4Al_2O_3(s)$

The $MnO_2$ is common on both side, by cancelling it, we get:

The net chemical equation for the production of manganese is:

$6MnCO_3(s)+3O_2(g)+8Al(s)\rightarrow 6CO_2(g)+6Mn(s)+4Al_2O_3(s)$

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3 years ago

BRAINLIESTTT ASAP!! PLEASE HELP ME :))

goldenfox [79]

Answer:

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Explanation:

The word "solar" means "relating to or denoting energy derived from the sun's rays".

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5 0

3 years ago

Read 2 more answers

How many moles of oxygen are present in 33.6l of the gas at 1atm and 0c

andreev551 [17]

The answer is: 1.5 moles of oxygen are present.

V(O₂) = 33.6 L; volume of oxygen.

p(O₂) = 1.0 atm; pressure of oxygen.

T = 0°C; temperature.

Vm = 22.4 L/mol; molar volume at STP (Standard Temperature and Pressure).

At STP one mole of gas occupies 22.4 liters of volume.

n(O₂) = V(O₂) ÷ Vm.

n(O₂) = 33.6 L ÷ 22.4 L/mol.

n(O₂) = 1.50 mol; amount of oxygen.

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3 years ago