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3 years ago

7

Make a He atom with a mass of 4. How many protons did you put in the nucleus?

2 answers:

VLD [36.1K]3 years ago

6 0

Answer:

<em>1.) Make a He atom with a mass of 4. How many protons did you put in the nucleus?</em>

<u>2</u>

<em>2.) Make a Li atom with a mass number of 7. How many electrons did you place in the outermost orbital (ring)?</em>

<u>1</u>

<em>3.) Make a N atom with a mass number of 14. How many neutrons are in the nucleus?</em>

<u>7</u>

<em>4.) Make a B atom with a mass number of 11. How many electrons did you put in the second orbital (ring)?</em>

<u>3</u>

Explanation:

<em>Did it on Edgenuity and got it correct (2020).</em>

FrozenT [24]3 years ago

5 0

Answer:

He has two protons

Li electron has one electron in its outermost orbital.

Number of neutrons of nitrogen = seven neutrons

The second shell of boron: 3 electrons.

Explanation:

An atom is composed of electrons, protons and neutrons. The number of neutrons is determined by subtraction of the atomic number from the mass number.

The electronic configuration is already known for each of atoms in these questions according to standard tables.

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Consider an exceptionally weak acid, HA, with a Ka = 1x10 -20 . You make a 0.1M solution of the salt Na

Vedmedyk [2.9K]

Answer:

$pH=13$

Explanation:

Hello,

In this case, given the acid, we can suppose a simple dissociation as:

$HA\rightleftharpoons H^+ + A^-$

Which occurs in aqueous phase, therefore, the law of mass action is written by:

$Ka=\frac{[H^+][A^-]}{[HA]}$

That in terms of the change $x$ due to the reaction's extent we can write:

$1x10^{-20}=\frac{x*x}{0.1M-x}$

But we prefer to compute the Kb due to its exceptional weakness:

$Kb=\frac{Kw}{Ka}=\frac{1x10^{-14}}{1x10^{-20}} =1x10^{-6}$

Next, the acid dissociation in the presence of the base we have:

$Kb=\frac{[OH^-][HA]}{[A^-]}=1x10^{6}=\frac{x*x}{0.1-x}$

Whose solution is $x=0.0999M$ which equals the concentration of hydroxyl in the solution, thus we compute the pOH:

$pOH=-log([OH^-])=-log(0.0999)=1$

Finally, since the maximum scale is 14, we can compute the pH by knowing the pOH:

$pH+pOH=14\\\\pH=14-pOH=14-1\\\\pH=13$

Regards.

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