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Orlov [11]
3 years ago
7

Make a He atom with a mass of 4. How many protons did you put in the nucleus?

Chemistry
2 answers:
VLD [36.1K]3 years ago
6 0

Answer:

<em>1.) Make a He atom with a mass of 4. How many protons did you put in the nucleus?</em>

<u>2</u>

<em>2.) Make a Li atom with a mass number of 7. How many electrons did you place in the outermost orbital (ring)?</em>

<u>1</u>

<em>3.) Make a N atom with a mass number of 14. How many neutrons are in the nucleus?</em>

<u>7</u>

<em>4.) Make a B atom with a mass number of 11. How many electrons did you put in the second orbital (ring)?</em>

<u>3</u>

Explanation:

<em>Did it on Edgenuity and got it correct (2020).</em>

FrozenT [24]3 years ago
5 0

Answer:

He has two protons

Li electron has one electron in its outermost orbital.

Number of neutrons of nitrogen = seven neutrons

The second shell of boron: 3 electrons.

Explanation:

An atom is composed of electrons, protons and neutrons. The number of neutrons is determined by subtraction of the atomic number from the mass number.

The electronic configuration is already known for each of atoms in these questions according to standard tables.

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What is the element presented, in this compound?
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4 0
3 years ago
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A selectively permeable membrane separates solution a and
Yakvenalex [24]
The water molecules will flow from b to a due to osmosis.

Osmosis is where water molecules will flow from a region of higher water potential to a region of lower water potential, through a selectively permeable membrane.

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3 0
3 years ago
1. What is the potential energy of a 8 kg ball that is at a height of 20 m?
weqwewe [10]

Answer:

1. 1568 J

2. 0 J

3. 1176 J

Explanation:

PE = mgh

(PE = Potential Energy) = (m = mass)(g = gravitational force which is 9.8)(h = height)

1. (3)(9.8)(20) = 1568 J

2. PE = (3)(9.8)(0) = 0 J

3. (5)(9.8)(24) =  1176 J

4 0
3 years ago
A standard solution contained 0.8 mg/mL. A student took 2 mL of the standard solution and added 10 mL of water. What is the new/
galben [10]
To get the concentration of the second solution let us use the following formulae

C1V1=C2V2 where C1 is concentration of first solution and V1 is the volume of solution first solution. on the other hand C2 is the concentration of second solution and V2 is the volume of second solution.

therefore

0.8×2=(2+10)×C2
   1.6 =12×C2
1.6/12=C2
C2     = 0.1333mg/mL
7 0
3 years ago
Read 2 more answers
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