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aleksandrvk [35]
3 years ago
7

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.

Chemistry
1 answer:
kirill [66]3 years ago
6 0
Molar mass :

H_2SO_4= 1*2+32+16*4= 98g/mol

Number of moles:

n =  \frac{solute}{molar( mass)}

n =  \frac{73.5g}{98g/mol}

n=0.75 (moles)

Volume = 3.0 L

M =  \frac{n}{V}

M =  \frac{0.75(moles)}{3.0L}

M = 0.25 mol/L ^{-1}

hope this helps!


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How many grams are in 1.23 x 1020 atoms of arsenic?
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<h3>Avogadro's hypothesis </h3>

6.02×10²³ atoms = 1 mole of arsenic

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1 mole of arsenic = 75 g

Thus, we can say that:

6.02×10²³ atoms = 75 g of arsenic

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6.02×10²³ atoms = 75 g of arsenic

Therefore,

1.23×10²⁰ atoms = (1.23×10²⁰ × 75) / 6.02×10²³ atoms)

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How much of a radioactive parent isotope will remain after three half-lives have passed?
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Many computer chips are manufactured from silicon, which occurs in nature as SiO2. When SiO2 is heated to melting, it reacts wit
riadik2000 [5.3K]

Answer:

A) SiO2 is the limiting reactant

B) Theoretical yield= 72333.3g

C) % yield =91.5%

Explanation:

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