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3 years ago

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.

1 answer:

6 0

Molar mass :

$H_2SO_4= 1*2+32+16*4= 98g/mol$

Number of moles:

$n = \frac{solute}{molar( mass)}$

$n = \frac{73.5g}{98g/mol}$

$n=0.75 (moles)$

Volume = 3.0 L

$M = \frac{n}{V}$

$M = \frac{0.75(moles)}{3.0L}$

$M = 0.25 mol/L ^{-1}$

hope this helps!

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What two elements are commonly found in Mica, Quartz and Feldspar? Explain your answer.

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Answer:

oxygen and silicon, both are common

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given two equations representing reactions: which type of reaction is represented by each of these equations?

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Answer:

Equation 1 - nuclear fission

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Nuclear fusion is a reaction in which two light nuclei combine in order to form a larger nuclei. This is clearly depicted in equation 2 as shown in the question.

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Read 2 more answers

Naturally occurring silicon has an atomic mass of 28.086 and consists of three isotopes. The major isotope is 28Si, natural abun

Elden [556K]

Answer:

29Si has a natural abundance of 4.68%.

30Si has a relative atomic mass of 29.99288 and a natural abundance of 3.09%.

Explanation:

The atomic mass of silicon is given by:

Si=Si²⁸×A₁+Si²⁹×A₂+Si³⁰×A₃

Where:

Si: atomic mass of silicon (28.086)

Si²⁸: relative atomic mass of 28Si (27.97693)

A₁: natural abundance of 28Si (92.23%)

Si²⁹: relative atomic mass of 29Si (28.97649)

A₂: natural abundance of 29Si

Si³⁰: relative atomic mass of 30Si

A₃: natural abundance of 30Si

We also know that 30Si natural abundance is in the ratio of 0.6592 to that of 29Si.

We have to set up a system of three equations in three unknowns:

Si=Si²⁸×A₁+Si²⁹×A₂+Si³⁰×A₃

A₃=0.6592×A₂

A₁+A₂+A₃=1

First, we find substitute the value of A₃ in the third equation and solv teh value of A₂:

A₁+A₂+0.6592×A₂=1

A₁+1.6592×A₂=1

1.6592×A₂=1-A₁

A₂= $\frac{1-A₁}{1.6592}=\frac{1-0.9223}{1.6592}$ =0.0468

Then, we find the value of A₃:

A₃=0.6592×A₂

A₃=0.6592×0.0468=0.0309

Finally, we find the value of Si³⁰ in the first equation:

Si=Si²⁸×A₁+Si²⁹×A₂+Si³⁰×A₃

28.086=27.97693×0.9223+28.97649×0.0468+Si³⁰×0.0309

28.086=27.15922+Si³⁰×0.0309

28.086-27.15922=Si³⁰×0.0309

$\frac{0.92678}{0.0309}$ =Si³⁰

Si³⁰=29.99288

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All organic compound soluble in WATEe and conduct electrically

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Explanation:

Not all organic substances are soluble in water and will not conduct electricity. Only polar organic compounds are soluble in water and will conduct electricity.

The general rule of solubility is that like dissolves likes.
Polar compounds will only dissolve other polar compounds too. Water is a polar solvent.
Non-polar compounds will only dissolve in non-polar compounds too.
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Not all organic compounds are polar.
When a compound dissolves in water, it produces ions that makes it able to conduct electricity.
Fats and oil are insoluble in water

learn more:

Inorganic compounds brainly.com/question/5047702

#learnwithBrainly

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