Question

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.

Answer 1

Molar mass :

$H_2SO_4= 1*2+32+16*4= 98g/mol$

Number of moles:

$n = \frac{solute}{molar( mass)}$

$n = \frac{73.5g}{98g/mol}$

$n=0.75 (moles)$

Volume = 3.0 L

$M = \frac{n}{V}$

$M = \frac{0.75(moles)}{3.0L}$

$M = 0.25 mol/L ^{-1}$

hope this helps!