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aleksandrvk [35]
3 years ago
7

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.

Chemistry
1 answer:
kirill [66]3 years ago
6 0
Molar mass :

H_2SO_4= 1*2+32+16*4= 98g/mol

Number of moles:

n =  \frac{solute}{molar( mass)}

n =  \frac{73.5g}{98g/mol}

n=0.75 (moles)

Volume = 3.0 L

M =  \frac{n}{V}

M =  \frac{0.75(moles)}{3.0L}

M = 0.25 mol/L ^{-1}

hope this helps!


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A solution which contains the maximum amount of solute is called a saturated solution. Whereas a solution in which more amount of solute is able to dissolve is called an unsaturated solution.

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So, a solution in which number of moles of NaCl are less than 0.616 mol per 100 mL then the solution formed will be an unsaturated solution.

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