3 years ago

Need help for financial algebra!! Plz

1 answer:

4 0

The answer should be $12

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Naddika [18.5K]

Answer:

Equation of line in slope-intercept form that passes through (4, -8) and is perpendicular to the graph $y= \frac {2}{5} x - 3$ is below

$y = - \frac {5}{2} x + 2$

Step-by-step explanation:

Slope of the equation $y= \frac{2}{5} x -3$ is $m_1 = \frac{2}{5}$

Since slopes of perpendicular lines are negative reciprocal of each other, therefore slope of other line is given as

$m_2 = - \frac {1}{m_1} = - \frac {5}{2}$

Equation of line in point slope form is given as

$y-y_1=m_2(x-x_1)$

Here (x1, y1) = (4, -8)

$y+8 = - \frac{5}{2} (x-4)$

Simplifying it further

$y = - \frac {5}{2} x + \frac {5}{2} 4 - 8$

$y = - \frac {5}{2} x + 2$

6 0

3 years ago

leonid [27]

Hello,
Please, see the attached file.
Thanks.

5 0

3 years ago

likoan [24]

1/4 = 5/20
2/5 = 8/20

8/20 + 5/20 = 13/20 has been spent

4 0

3 years ago

MatroZZZ [7]

Point H shows 45 because 6.7 multiplied by each other equals 45 and 6.7 on the line is point H

7 0

3 years ago

Alisiya [41]

In your calculator, input arcsin(7/12). Make sure that your calculator is in degree mode. The answer is 35.69 degrees.

3 0

3 years ago