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3 years ago

Cost of sled $99.50 markup 95%

Mathematics

1 answer:

DIA [1.3K]3 years ago

8 0

Sled $99.50 X 0.95= $94.525
$94.525+ $99.50 = $194.025
Answer is $194.03

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3 years ago

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QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu

Harman [31]

Answer:

(a)Revenue function, $R(x)=580x-x^2$

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit, $P(x)=-35x^2+280x-900$

(d)x=4

Step-by-step explanation:

Part A

Price Function $= 580 - 10x$

The revenue function

$R(x)=x\cdot (580-10x)\\R(x)=580x-x^2$

The marginal revenue function

$\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x$

Part B

(Fixed Cost)

The total cost function of the company is given by $c=(30+5x)^2$

We expand the expression

$(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2$

Therefore, the fixed cost is 900 .

Marginal Cost Function

If $c=900+300x+25x^2$

Marginal Cost Function, $\frac{dc}{dx}= (900+300x+25x^2)'=300+50x$

Part C

Profit Function

Profit=Revenue -Total cost

$580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900$

Part D

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

$P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4$

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Answer:

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Step-by-step explanation:

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3 years ago

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There may be more than one way in which to answer this question. I will assume that the "equation" is a linear one: f(x) = mx + b.

Then (16/3) = m(1) + b
This is one equation in two unknowns, so it does not have a unique solution. Was there more to this problem than you have shared?

If we assume that the y-intercept (b) is zero, then y = mx, and

16/3 = 1m, so that m = 16/3, and so y = (16/3)x.

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3 years ago

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ICE Princess25 [194]

Answer:

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Statement: AC=AC

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Step-by-step explanation:

1.Statement: $\angle ABC\cong \angle BCD,\angle BAD\cong \angle ADC$ .