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iris [78.8K]
2 years ago
6

What is 9×1+2×1/10+6×1 100 written in standard form

Mathematics
2 answers:
levacccp [35]2 years ago
8 0

Answer:

600+0+9+0.2

Step-by-step explanation:

ad-work [718]2 years ago
3 0

Use PEMDAS:

So, 9+2 / 10+6,600

Finally, 11 / 6610

So the answer is 11 / 6610

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Y = 5x + 1<br> 4x + y = 10<br> System of equations
HACTEHA [7]
Substitution or elimination
3 0
2 years ago
Use implicit differentiation to find the points where the parabola defined by x2−2xy+y2+4x−8y+20=0 has horizontal and vertical t
Komok [63]

Answer:

The parabola has a horizontal tangent line at the point (2,4)

The parabola has a vertical tangent line at the point (1,5)

Step-by-step explanation:

Ir order to perform the implicit differentiation, you have to differentiate with respect to x. Then, you have to use the conditions for horizontal and vertical tangent lines.

-To obtain horizontal tangent lines, the condition is:

\frac{dy}{dx}=0 (The slope is zero)

--To obtain vertical tangent lines, the condition is:

\frac{dy}{dx}=\frac{1}{0} (The slope is undefined, therefore the denominator is set to zero)

Derivating respect to x:

\frac{d(x^{2}-2xy+y^{2}+4x-8y+20)}{dx} = \frac{d(x^{2})}{dx}-2\frac{d(xy)}{dx}+\frac{d(y^{2})}{dx}+4\frac{dx}{dx}-8\frac{dy}{dx}+\frac{d(20)}{dx}=2x -2(y+x\frac{dy}{dx})+2y\frac{dy}{dx}+4-8\frac{dy}{dx}= 0

Solving for dy/dx:

\frac{dy}{dx}(-2x+2y-8)=-2x+2y-4\\\frac{dy}{dx}=\frac{2y-2x-4}{2y-2x-8}

Applying the first conditon (slope is zero)

\frac{2y-2x-4}{2y-2x-8}=0\\2y-2x-4=0

Solving for y (Adding 2x+4, dividing by 2)

y=x+2 (I)

Replacing (I) in the given equation:

x^{2}-2x(x+2)+(x+2)^{2}+4x-8(x+2)+20=0\\x^{2}-2x^{2}-4x+x^{2} +4x+4+4x-8x-16+20=0\\-4x+8=0\\x=2

Replacing it in (I)

y=(2)+2

y=4

Therefore, the parabola has a horizontal tangent line at the point (2,4)

Applying the second condition (slope is undefined where denominator is zero)

2y-2x-8=0

Adding 2x+8 both sides and dividing by 2:

y=x+4(II)

Replacing (II) in the given equation:

x^{2}-2x(x+4)+(x+4)^{2}+4x-8(x+4)+20=0\\x^{2}-2x^{2}-8x+x^{2}+8x+16+4x-8x-32+20=0\\-4x+4=0\\x=1

Replacing it in (II)

y=1+4

y=5

The parabola has vertical tangent lines at the point (1,5)

4 0
3 years ago
PLEASE HELP!<br>(I know its not math, stop hatin!)<br>(If a human and a dog were the same)
Vaselesa [24]

Answer:

1st one

Step-by-step explanation

I have NEVER in my life seen a dog with pants on its back legs, only on both so yeah.

4 0
3 years ago
True or False. The graph below is a function. -10 8 6 4 2 -10 -8 -6 -4 -2 2 4 6 8 10 -2 + -4 -6- -8 -10 True False​
belka [17]

Answer:

false

Step-by-step explanation:

numbers are repeating

6 0
2 years ago
What is this one again?
natka813 [3]
I believe it’s C but I don’t know 100%
5 0
3 years ago
Read 2 more answers
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