Question

You are studying two linked genes that influence vine height and fruit color in squash. Yellow color is dominant over green, and tall height is dominant over short. You get the following numbers of offspring from your testcross: 198 Tall Yellow, 192 Short Green, 54 Tall Green, and 56 Short Yellow What is the distance between these genes?

Answer 1

Answer:

22 map units

Explanation:

Linked genes may be defined as the genes present on the same chromosomes and they are inherited to the next progeny. The linked genes produces the recombinant progeny.

Distance between the linked gene = No. of recombinants / total number × 100.

Here the parental are 198 Tall Yellow, 192 Short Green.

The recombinant progeny are 54 Tall Green, and 56 Short Yellow.

Distance = $\frac{54+56}{198+192+54+56}\times100$

Distance = $\frac{110}{500}\times100$

Distance = 22 map units.

So, the distance between the genes are 22 map units.