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3 years ago

15

What is the value of v? 29v 4−23v=5 enter your answer in the box.?

1 answer:

adell [148]3 years ago

3 0

6
iuytgfdsfrgthyjikjuhgf sorry please medal ;p

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Efectuati calculele:

NNADVOKAT [17]

$\sqrt{(5 - 1)^{2}} + \sqrt{20}$

$\sqrt{4^{2}} + \sqrt{4 * 5}$

$\sqrt{16} + \sqrt{4} \sqrt{5} 
$

$4 + 2 \sqrt{5} 
$

$4\sqrt{5} + 2 \sqrt{5} 
$

$6 \sqrt{5}$

$\sqrt{(10 - 3)^{2}} + \sqrt{20 * 18}$

$\sqrt{7^{2}} + \sqrt{4 * 9 * 5 * 2}$

$\sqrt{49} + \sqrt{36 * 10}$

$7 + \sqrt{36}\sqrt{10}$

$7 + 6\sqrt{10}$

$7\sqrt{10} + 6\sqrt{10}$

$13\sqrt{10}$

$\sqrt[3]{(3 + 1)^{2}} - \sqrt{(3 - 2)x^{2}$

$\sqrt[3]{4^{2}} - \sqrt{x^{2}$

$\sqrt[3]{16} - x[tex] \\[tex] \sqrt[3]{8 * 2} - x$

$\sqrt[3]{8} \sqrt[3]{2} - x
$

$2\sqrt[3]{2} - x$

8 0

3 years ago

-13m = 1 - 14m what is the answer

salantis [7]

Answer:

m = 1

Step-by-step explanation:

<u>Step 1: Add 14m to both sides</u>

-13m + 14m = 1 - 14m + 14m

<em>m = 1</em>

<em />

Answer: m = 1

6 0

2 years ago

A certain television is advertised as a 55-inch TV (the diagonal length). If the width of the TV is 42 inches, how many inches t

Mumz [18]

Answer:

69.20in

Step-by-step explanation:

Given data

diagonal of the TV d= 55in

Widht of the TV w= 42 in

Hight h= ???

Applying the Pythagoras theorem

d^2= w^2+ h^2

substitute

55^2= 42^2+ h^2

3025= 1764+ h^2

3025+1764= h^2

4789= h^2

h=√4789

h= 69.20

Hence the Heigth is 69.20in

7 0

2 years ago

Helppppppppppppp meeee plsssssss.

maria [59]

Answer:

C

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If you are going 43.5 miles per hour how many feet per second are you traveling?

Olenka [21]

Answer:

63.7999... (repeating) fps

Step-by-step explanation:

Feet per second (fps) per one (1) mph is 1.4666... repeating

so 43.5 * 1.46666... = 63.7999.. repeating

hope this helps:)

5 0

2 years ago