Answer: 49 ten thousands + 2 thousands + 6 hundreds + 2 tens + 3 ones
another way
492 thousands + 62 tens + 3 ones
another way
4926 hundreds + 23 ones
Step-by-step explanation:
Answer:
Step-by-step explanation:
Question 1 = 2002
2002 - 2000 = 2 (the years since 2000)
y = (275 x 2) + 50
y = 875
Question 2 = 1425 likes
2005 - 2000 = 5 (the years since 2000)
y = (275 x 5) + 50
y = 1425
Question 3 = 2018
Since y = 5000
5000 - 50(the extra likes) = 4950
4950 / 275 = 18 (the years since 2000)
2000 + 18 = 2018 (the year)
Answer:

Step-by-step explanation:
This question is on rules of rational exponential
where the exponential is a fraction, you can re-write it using radicals where the denominator of the fraction becomes the index of the radical;
<u>General expression </u>
![a^\frac{1}{n} =\sqrt[n]{a}](https://tex.z-dn.net/?f=a%5E%5Cfrac%7B1%7D%7Bn%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D)
Thus ![\sqrt[3]{x} =x^\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3Dx%5E%5Cfrac%7B1%7D%7B3%7D)
<u>Applying the same in the question </u>
![\sqrt[3]{x^5y} =x^\frac{5}{3} y^\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E5y%7D%20%3Dx%5E%5Cfrac%7B5%7D%7B3%7D%20y%5E%5Cfrac%7B1%7D%7B3%7D)
=
Answer:
-2
Step-by-step explanation:
the input, or domain is always replacing x
y=-2x+6
y=-2(4)+6
y=-8+6
y=-2
Answer:
9/25
Step-by-step explanation:
find a number that both the top and bottom are divisible by,
23 is the greatest common division we can make such that the top and bottom remain whole numbers
so,
÷23
=(207/23)÷(575/23)
=