Answer:
13 Ocicats
Step-by-step explanation:
Here, we are told that an Ocicat eats 3/5 pounds of food per day.
Now, we have a bag of 19 1/2 pound of food and we want to know the number of Ocicats this will feed
What we just need to do is to divide the weight of the bag by the amount in pounds that can feed a single Ocicat
Thus, we have;
19 1/2 divided by 3/5
= 39/5 divided by 3/5
= 39/5 * 5/3
= 13 Ocicats
Answer:
The slope is 2/3
Step-by-step explanation:
To find the slope of a line
m = (y2-y1)/(x2-x1)
= (1--1)/(0--3)
= (1+1)/(0+3)
= 2/3
Answer:
a. p(orange) = 5/14
b. p(green) = 3/14
c. p(red) = 1/7
d. p(brown) = 2/7
e. p(brown or red) = 3/7
Step-by-step explanation:
1. You have a 14 pencils. Two pencils are red, 5 pencils are orange, 3 pencils are green and 4 pencils are brown.
p(color) = (number of pencils of that color)/(total number of pencils)
p(color) = (number of pencils of that color)/14
a. If a pencil is picked at random, what is the probability that the pencil
will be orange?
p(orange) = 5/14
b. If a pencil is picked at random, what is the probability that the pencil
will be green?
p(green) = 3/14
c. If a pencil is picked at random, what is the probability that the pencil will be red?
p(red) = 2/14 = 1/7
d. If a pencil is picked at random, what is the probability that the pencil
will be brown?
p(brown) = 4/14 = 2/7
e. If a pencil is picked at random, what is the probability that the pencil
will be brown or red?
brown: 4
red: 2
brown or red: 4 + 2
p(brown or red) = 6/14 = 3/7
Answer:
Max's paper airplane flew
feet or
feet.
Step-by-step explanation:
As Nora's paper airplane flew 9 1/6 feet
i.e.
![9\frac{1}{6}=\frac{55}{6}](https://tex.z-dn.net/?f=9%5Cfrac%7B1%7D%7B6%7D%3D%5Cfrac%7B55%7D%7B6%7D)
Nora's paper was farther than Max's plane flew by = 2 3/4 feet
i.e.
![2\frac{3}{4}=\frac{11}{4}](https://tex.z-dn.net/?f=2%5Cfrac%7B3%7D%7B4%7D%3D%5Cfrac%7B11%7D%7B4%7D)
Thus the equation to show how far Max's paper airplane flew is:
![\:\:9\frac{1}{6}-2\frac{3}{4}](https://tex.z-dn.net/?f=%5C%3A%5C%3A9%5Cfrac%7B1%7D%7B6%7D-2%5Cfrac%7B3%7D%7B4%7D)
![=\frac{55}{6}-\frac{11}{4}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B55%7D%7B6%7D-%5Cfrac%7B11%7D%7B4%7D)
![\mathrm{Least\:Common\:Multiplier\:of\:}6,\:4:\quad 12](https://tex.z-dn.net/?f=%5Cmathrm%7BLeast%5C%3ACommon%5C%3AMultiplier%5C%3Aof%5C%3A%7D6%2C%5C%3A4%3A%5Cquad%2012)
![\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}](https://tex.z-dn.net/?f=%5Cmathrm%7BAdjust%5C%3AFractions%5C%3Abased%5C%3Aon%5C%3Athe%5C%3ALCM%7D)
![=\frac{110}{12}-\frac{33}{12}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B110%7D%7B12%7D-%5Cfrac%7B33%7D%7B12%7D)
![\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}](https://tex.z-dn.net/?f=%5Cmathrm%7BSince%5C%3Athe%5C%3Adenominators%5C%3Aare%5C%3Aequal%2C%5C%3Acombine%5C%3Athe%5C%3Afractions%7D%3A%5Cquad%20%5Cfrac%7Ba%7D%7Bc%7D%5Cpm%20%5Cfrac%7Bb%7D%7Bc%7D%3D%5Cfrac%7Ba%5Cpm%20%5C%3Ab%7D%7Bc%7D)
![=\frac{110-33}{12}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B110-33%7D%7B12%7D)
![\mathrm{Subtract\:the\:numbers:}\:110-33=77](https://tex.z-dn.net/?f=%5Cmathrm%7BSubtract%5C%3Athe%5C%3Anumbers%3A%7D%5C%3A110-33%3D77)
![=\frac{77}{12}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B77%7D%7B12%7D)
![=6\frac{5}{12}](https://tex.z-dn.net/?f=%3D6%5Cfrac%7B5%7D%7B12%7D)
Therefore, Max's paper airplane flew
feet or
feet.
Answer:
need more info none of this makes sense?!??!?
Step-by-step explanation: