Answer: (12) ∠1 = 20° (13) ∠2 = 50° (14) ∠3 = 15° (15) UV = 80° (16) AB = 40° (17) ABC <em>or</em> 180° - CD (18) BC - 140° (19) ABC = 150°
<u>Step-by-step explanation:</u>
12)
(UV - ST) = ∠1
(80 - 40) = ∠1
(40) = ∠1
20 = ∠1
13)
(UV + ST) = ∠2
(70 + 30) = ∠2
(100) = ∠2
50 = ∠2
14)
(VB - BS) = ∠3
(60 - 30) = ∠3
(30) = ∠3
15 = ∠3
15)
(UV - ST) = ∠1
(UV - 20) = 30
UV - 20 = 60
UV = 80
16) ∠1 = arc AB
∠1 = 40
arc AB = 40
17) arc AB + arc BC = arc AC
= 180 = arc CD
18) ∠1 + ∠2 + ∠3 = 180
20 + ∠2 + 20 = 180
∠2 + 40 = 180
∠2 = 140
19) ∠1 + ∠ 2 = arc ABC
∠1 + ∠2 + ∠3 = 180
arc ABC + 30 = 180
arc ABC = 150
Answer:
I think the answer is A
Step-by-step explanation:
I'm not sure tho
(Hard) A composite number n is called a Carmichael number bn−1 ≡ 1 (mod n) for every number b such ... Base case: When n = 2 the formula a + c ≡ b + d (mod m) was already given. ... The sequence goes 1, 3, 7, 15, 31,... guess that it is equal to 2n+1 − 1. ... Prove (now using induction on n) that fm|fmn for all n ≥ 1.
Answer:
The inequality x>2 matches the graph.
Step-by-step explanation:
From the graph, it is clear that the shaded graph is heading towards the +ve infinity from the x > 2.
If the inequality includes < or >, we graph the equation as a dotted line.
From the graph, the dotted line indicates that x=2 is not included in the solution of the inequality.
so the interval of the domain of the inequality is: (2, ∞)
Therefore, the inequality x>2 matches the graph.