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antiseptic1488 [7]
3 years ago
15

Just HELP with questions 1 and 2 please thanks a lot

Mathematics
1 answer:
DanielleElmas [232]3 years ago
5 0
2. 5, 10, and 20 are factors of 20 that are not also factors of 12.
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2.98 times 0.6 = 1.794
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On a trip of d miles to another city, a truck driver's average speed was x miles per hour. On the return trip, the average speed
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Mile x was 15 miles long per hour while Y was 15 miles per hour on the two trips
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3 years ago
5x+6y=18and 18x-15y=36<br> parallel or perpendicular
Katen [24]

Answer:

<u>They</u><u> </u><u>are</u><u> </u><u>neither</u><u> </u><u>parallel</u><u> </u><u>nor</u><u> </u><u>perpendicular</u><u>,</u><u> </u><u>since</u><u> </u><u>slope</u><u> </u><u>are</u><u> </u><u>different</u><u> </u><u>and</u><u> </u><u>not</u><u> </u><u>related</u><u> </u><u>by</u><u> </u><u>any</u><u> </u><u>equation</u>

Step-by-step explanation:

First arrange them according to general equation:

y = mx + c

<u>f</u><u>o</u><u>r</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>f</u><u>i</u><u>r</u><u>s</u><u>t</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u> :

5x + 6y = 18 \\ 6y =  - 5x + 18 \\ { \boxed{y =  -  \frac{5}{6} x + 3}}

<u>f</u><u>o</u><u>r</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u> :

18x - 15y = 36 \\ 15y = 18x - 36 \\ y =  \frac{18}{15} x -   \frac{12}{5}

8 0
3 years ago
Help me with this please
Angelina_Jolie [31]
It’s the last one. b < c < a
4 0
3 years ago
Two students walk in the same direction along a straight path, at a constant speed - one at .90 m/s and the other at 1.90 m/s.a.
anyanavicka [17]

Answer:

a)The second student arrive 7 minutes and 36 seconds sooner

b)They have to walk 598,51 m

Step-by-step explanation:

Speed= Distance/Time

We are looking for time now

Time = Distance/Speed

First student

Time = 780 m/0.90 m/s=866,66 seconds

Second student

Time = 780 m/1.90 m/s=410,52 seconds

Difference=866,66-410,52= 456,14 seconds

In minutes

Difference= 456,14 seconds /60=7 minutes 36 seconds

Distance=Speed x Time

Speed¹ x Time¹ =Speed² x Time²

Time¹= Time² + 5.50 min

5.50 min =350 seconds

Time²  =Speed¹ x Time¹ /Speed²

Time²  =Speed¹ x (Time² + 350 seconds  ) /Speed²

Time²  =0.9 x (Time² + 350 seconds  ) /1.9

Time²  =0,4737 x (Time² + 350 seconds  )

Time²  =0,4737 Time² + 165,79 seconds

Time²  - 0,4737 Time² = 165,79 seconds

0,5263 Time² = 165,79 seconds

Time² = 165,79 seconds/0,5263 =315,01 seconds

Distance=1,9 x 315,01 seconds = 598,51 m

5 0
3 years ago
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