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OlgaM077 [116]
3 years ago
8

Which expression is equivalent to (2g^3+4)^2

Mathematics
2 answers:
Jet001 [13]3 years ago
5 0

Answer with explanation:

Two expression are said to be equivalent, if we replace the variable by some constant say 'w' in both the expressions the two expression , that is original expression and Equivalent expression yields the same numerical value.

The given expression is:

 (2 g^3 +4)^2=(2 g^3)^2+4^2+2 \times (2 g^3) \times 4\\\\=4 g^6+16 +16 g^3

is an equivalent expression of the expression given.

Used the identity

⇒(a +b)²=a²+b²+2 a b

Brrunno [24]3 years ago
4 0

Answer:

+64g^6 + 64g^3 + 16. I think

Explanation:

{( {2g}^{3}  +4)}^{2}  = {(8 {g}^{3}  + 4) }^{2} =

(8 {g}^{3}  + 4) \times(8 {g}^{3}  + 4) = 64 {g}^{6}  + 32 {g}^{3}  + 32 {g}^{3} + 16 = 64 {g}^{6}  + 64 {g}^{3}  + 16

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</span><span>by the ratio and proportion

∴ </span>Height of Jacob/Jacob's shadow = Height of giraffe/giraffe's shadow

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Find the least common factor denominator for these two rational 7/x^2 and 7/5x
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Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

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