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Mrrafil [7]
3 years ago
13

10-25 I know that a lot but I am terriable at math and don't understand this so please help

Mathematics
1 answer:
shtirl [24]3 years ago
5 0
10. x = 3
13. -x+6/3x
16. 2x^2/x
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Choose the graph that represents the following system of inequalities:
Licemer1 [7]

Answer:

FIRST.

64 square inches matches to a cross section parallel to the base of a right rectangle prism that is 3 inches long, 7 inches wide, and 11 inches tall

This is shown in the first figure below. A right rectangular prism where every edge connecting its base and the opposite face makes right angles with both faces. Since the tall is the side that measures 11 inches, then the base is formed by 3 inches long and 7 inches wide. Therefore, the area of this shape can be found as the area of a rectangle, which is: 21 in squared.

SECOND.

64 square inches matches to a cross section parallel to the base of a cube whose edges are 8 inches long.

This is shown in the second figure below. A cube is a prism whose sides all have the same length and in this case is 8 inches. We name cross section is to the slice that cuts through a solid. If the cross section is parallel to the base of a cube, then it forms a square with length . Therefore, the area of this shape can be found as the area of a square, which is: 64 in squared.

Third.

7 square inches matches to a cross section passing through the diagonal of opposite faces of a cube with edges that are 7 inches long and a diagonal that is approximately 10 inches

This is shown in the third figure below. As you can see, the cross section passes through the diagonals of the base and the top of the cube that are two opposite faces. This form a rectangle having sides  where:

So: 70 in squared

FOURTH.

300 square inches matches to a cross section perpendicular to the base and passing through the diagonals of the base and opposite face of a right rectangular prism that is 24 inches wide, 7 inches long, and 12 inches tall and measures 25 inches along the diagonal of the base.

This is shown in the fourth figure below. The cross section passes through the diagonals of the base and the top of the right rectangular prism. They are opposite to each other, so the shape of the cross section is a rectangle whose sides are  where:

So: 300 in squared.

Step-by-step explanation:

6 0
3 years ago
A bag of marbles contains 6 blue marbles, 2 yellow marbles, 4 red marbles, and 1 green marble. What is the probability of
const2013 [10]

Answer:

2/13

Step-by-step explanation:

add them all up then divide by the yellow

3 0
3 years ago
Scores on the test are normally distributed with a mean of 79 and a standard deviation of 8.4. Find the numerical limits for a B
Oksanka [162]

This is not the question, the correct question is:

A humanities professor assigns letter grades on a test according to the following scheme. A: Top 6% of scores B: Scores below the top 6% and above the bottom 59% C: Scores below the top 41% and above the bottom 17% D: Scores below the top 83% and above the bottom 7% F: Bottom 7% of scores.

Scores on the test are normally distributed with a mean of 79 and a standard deviation of 8.4. Find the numerical limits for a B grade. Round your answers to the nearest whole number, if necessary.

Answer:  The numerical limits for grade B is 81 and 92

Step-by-step explanation:

Given that

mean Ж = 79

Standard deviation S = 8.4

B: Scores below the top 6% and above the bottom 59%

To find the numerical value for Grade B

Below the top bottom 6% ( 0.06) is

p ( X < Ж ) = 1 - 0.06

p ( X < Ж ) = 0.94

therefore

P( (X - ц)/S < (X - Ж) / S)) = 0.94

(X - 79) / 8.4 = 1.5548 ( from normal distribution table )

X - 79 = 13.0603

X = 13.0603 + 79

X = 92.06 ≈ 92 ( nearest whole number)

Above bottom 59% ( 0.59) is

p ( X < Ж ) = 0.59

therefore

P( (X - ц)/S < (X - Ж) / S)) = 0.59

(X - 79) / 8.4 = 0.2275 ( from normal distribution table )

X - 79 = 1.9114

X = 1.9114 + 79

X = 80.91 ≈ 81 ( nearest whole number)

So the numerical limits for grade B is 81 and 92

3 0
3 years ago
In a certain​ chemical, the ratio of zinc to copper is 3 to 11. A jar of the chemical contains 385 grams of copper. How many gra
Tomtit [17]

Answer:

35 grams

Step-by-step explanation:

The ratio of zinc to copper is 3 to 11

A jar of chemical contains 385 grams if copper

Therefore the number of grams of zinc it contains can be calculated as follows

3/11= x/385

11x= 385

x= 385/11

= 35 grams

Hence the chemical contains 35 grams of zinc

4 0
3 years ago
1 million selfies taken each day on average, 48% are posted How many selfies are posted to the site each day?
Igoryamba

Answer:

480,000

Step-by-step explanation:

1,000,000 x 0.48 = 480,000

480,000 = 48% of 1 million

7 0
3 years ago
Read 2 more answers
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