y=2/3y-3
1. y = 2/3 (9)-3 multiply 9 and 2 =18/3
y=18/3-3 divide 18 and 3 =6
y=6-3 subt. 3
y=3
2. -11=2/3x - 3
-11+3 = 2/3 x add 3 to both sides to cancel -3
-8=2/3 x
(3/2)-8 = (2/3)3/2 x multiply both sides by reciprical of 2/3
-24/2 = x divide
-12=x
Answer:
The length of the diagonal HJ is 10.82 units
Step-by-step explanation:
* Lets revise the rule of the distance between two points
-
, where
and
are the two points
* Lets use this rule to find the length of the diagonal HJ
∵ The coordinates of point H are (-4 , 3)
∵ The coordinates of point J are (5 , -3)
∴
and 
∴
and 
- Lets find the length of the diagonal HJ by using the rule above
∴ HJ = 
∴ HJ = 
∴ HJ = 10.82
* The length of the diagonal HJ is 10.82 units
Answer:
416 miles
Step-by-step explanation:
78 divided by 3 = 26
26 x 16 = 416