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2 years ago

Help please Solving Systems Using Inspection

Mathematics

2 answers:

Kamila [148]2 years ago

6 0

The lines appear to be parallel. We can check this out by examining the
two equations, and we see that sure enough, both lines have the same
slope (1/2) so they're definitely parallel. Parallel lines never intersect,
so this pair of equations has NO solutions. NONE. Zero. Bubkes. Nada.

pashok25 [27]2 years ago

3 0

The Other dude is correct I did the test

The answer is None

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Simplify expressions

charle [14.2K]

<h3>a) $\frac{2}{5} \div ( - \frac{3}{4} )$ </h3><h3>■Dividing a positive and a negative equals a negative: (+)÷(-)=(-)</h3>

<h2> $- \frac{2}{5} \div \frac{3}{4}$ </h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2> $- \frac{2}{5} \times \frac{4}{3}$ </h2><h3>■Multiply the fractions</h3>

<h3>Hence, Quotient = $- \frac{8}{15}$ </h3>

<h3>b) $0.4 \div ( - 0.75)$ </h3><h3>■Convert the decimals into a fractions</h3>

<h2> $\frac{2}{5} \div ( - \frac{3}{4} )$ </h2><h3>■Dividing a positive and a negative equals a negative: (+)÷(-)=(-)</h3>

<h2> $- \frac{2}{5} \div \frac{3}{4}$ </h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2> $- \frac{2}{5} \times \frac{4}{3}$ </h2><h3>■Multiply the fractions</h3>

<h2> $- \frac{8}{15}$ </h2><h3>Hence, Quotient is $- \frac{8}{15}$ </h3>

<h3>c) $- \frac{2}{5} \div \frac{3}{4}$ </h3><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2> $- \frac{2}{5} \times \frac{4}{3}$ </h2><h3>■Multiply the fractions</h3>

<h2> $- \frac{8}{15}$ </h2><h3>Hence, The Quotient is $- \frac{8}{15}$ </h3>

4 0

2 years ago

Please help me out :c - I will mark brainliest

andrew-mc [135]

Answer:

6.6%

Step-by-step explanation:

6 0

2 years ago

Jeffery babysits for 4 dollars per hour, he also works as a math tutor for 7 dollars per hour. He is only allowed to work 13 hou

Oksana_A [137]

Given:

Jeffery babysits for 4 dollars per hour and works as a math tutor for 7 dollars per hour.

He is only allowed to work 13 hours total per week.

He wants to make at least 65 dollars.

To find:

The system of inequalities to represent this situation.

Solution:

Let x be the number of hours he babysits per week and y be the number of hours h works as a math tutor.

He is only allowed to work 13 hours total per week. It means sum of x and y must be less than or equal to 13.

$x+y\leq 13$

He wants to make at least 65 dollars. It means total earnings must be greater than or equal to 65.

$4x+7y\geq 65$

Number of hours can not be negative.

$x\geq 0, y\geq 0$ .

Therefore, the required system of inequalities contains some equations, $x+y\leq 13,4x+7y\geq 65$ and $x, y\geq 0$ .

4 0

2 years ago

13-6x=(2x-5)^2+3 what answer

svet-max [94.6K]

<span><span>13−<span>6x</span></span>=<span><span><span>(<span><span>2x</span>−5</span>)</span>2</span>+3</span></span>Step 1: Simplify both sides of the equation.<span><span><span>−<span>6x</span></span>+13</span>=<span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span></span>Step 2: Subtract 4x^2-20x+28 from both sides.<span><span><span><span>−<span>6x</span></span>+13</span>−<span>(<span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span>)</span></span>=<span><span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span>−<span>(<span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span>)</span></span></span><span><span><span><span>−<span>4<span>x2</span></span></span>+<span>14x</span></span>−15</span>=0</span>Step 3: Use quadratic formula with a=-4, b=14, c=-15.<span>x=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>x=<span><span><span>−<span>(14)</span></span>±<span>√<span><span><span>(14)</span>2</span>−<span><span>4<span>(<span>−4</span>)</span></span><span>(<span>−15</span>)</span></span></span></span></span><span>2<span>(<span>−4</span>)</span></span></span></span><span>x=<span><span><span>−14</span>±<span>√<span>−44</span></span></span><span>−<span>8</span></span></span></span>

5 0

2 years ago

Write 90 as a product of prime factors in expanded form.

NISA [10]

Given :

The number is given as 90.

Explanation :

To find the product of prime factors in expanded form

$90=2\times3\times3\times5$

Answer :

Hence the answer is

$90=2\times3\times3\times5$

5 0

10 months ago