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4 years ago

I have a two in one question and kind of need it fast!

Mathematics

1 answer:

AleksAgata [21]4 years ago

5 0

0.00969339 mi/min

1.76 l/min

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5 1/3 divided by 4/A

BlackZzzverrR [31]

Answer:

$5 \frac{1}{3} \div \frac{4}{a} \\ \frac{16}{3} \div \frac{4}{a} \\ \frac{16}{3} \times \frac{a}{4} \\ \frac{4}{3} \times a \\ \frac{4a}{3} \\$

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3 years ago

4/X divided by 6/1 = 1/12 <br> What is x and how do I find it. I’m truly confused.

Svetradugi [14.3K]

The answer to your question

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4 years ago

There are 45 questions on your math exam. You answered 810810 of them correctly. How many questions did you answer correctly?

Dominik [7]

You answered all of them if there is only 45 and you answered 810810.

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4 years ago

<img src="https://tex.z-dn.net/?f=cos%20%5B%20arctan%28%5Cfrac%7B12%7D%7B5%7D%29%20-%20arcsin%20%28%5Cfrac%7B-3%7D%7B5%7D%29%5D"

qwelly [4]

Answer: -16/65

Step-by-step explanation:

Drawing the right triangle (as attached) gives us that $\arctan \left(\frac{12}{5} \right)=\arcsin \left(\frac{12}{13} \right)$

Also, $-\arcsin \left(-\frac{3}{5} \right)=\arcsin \left(\frac{3}{5} \right)$

This means our original expression is equal to:

$\cos \left[\arcsin \left(\frac{12}{13} \right)+\arcsin \left(\frac{3}{5} \right) \right]$

Using the cosine addition formula, which states $\cos(a+b)=\cos a \cos b-\sin a \sin b$ , we get this itself is equal to:

$\cos \left(\arcsin \left(\frac{12}{13} \right) \right)\cos \left(\arcsin \left(\frac{3}{5} \right)\right)-\sin \left(\arcsin \left(\frac{12}{13} \right) \right)\sin \left(\arcsin \left(\frac{3}{5} \right)\right)$

Since $\sin^{2} \theta+\cos^{2} \theta=1$ , we know that:

$\sin^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)+\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\\frac{144}{169} +\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{25}{169}\\\\cos \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{5}{13}$

Similarly, cos(arcsin(3/5))=4/5.

This means the given expression is equal to:

$\left(\frac{5}{13} \right) \left(\frac{4}{5} \right)-\left(\frac{12}{13} \right) \left(\frac{3}{5} \right)\\\\\frac{20}{65}-\frac{36}{65}=\boxed{-\frac{16}{65}}$

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2 years ago

What the square of 8^2

Novosadov [1.4K]

Answer:

8^2 = 64

unless you mean 8^2's square root then it is 8

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers