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Olenka [21]
3 years ago
12

What is 3/32 + 1/8 =​

Mathematics
2 answers:
kirill115 [55]3 years ago
4 0
I believe 7/32
or an alternative form: 0.21875
ANTONII [103]3 years ago
4 0
7/32 . or .21875 . i’m frl
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Please help with 2 and 3 for maths
Vera_Pavlovna [14]

Answer:2-4=

Step-by-step explanation:y-16-(-42)

y-16+16

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y-16-(-22)

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8 0
2 years ago
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Which equation has the solution x = 3?
arsen [322]
Well, let's first solve each equation:

1.) -4x + 6 - 3x = 12 - 2x - 3x

To start, combine each like-term on each side of the equal sign (The numbers with variables in-common // the numbers alike on the same side of the equal sign):

-7x + 6 = 12 - 5x

Now, we get the two terms with variables attached to them, on the same side, so, we do the opposite of subtraction, which is, addition:

-7x + 6 = 12 - 5x
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-2x + 6 = 12

Next, you do the opposite of addition, which is, subtraction, and, subtract 6 from both sides:

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Finally, divide by -2 on each side, to find out what the value of 'x' is:

-2x = 6
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So, the answer is not 'A.'
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Now, we test out the rest of the equations, the exact same way:

2.) 4x + 6 + 3x = 12 + 2x + 3x

Combine your like-terms, on each side of the equal sign:

7x + 6 = 12 + 5x

Now, get both terms, with the variable, 'x,' to the same side, and, to do that, do the opposite of addition, which is, subtraction:

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3.) 4x + 6 - 3x = 12 - 2x - 3x

Again, we combine the like-terms, on both sides of the equal sign:

x + 6 = 12 - 5x

Now, we get both terms with the variable 'x,' to the same side, and, the opposite of subtraction, is addition, so, we're going to add 5x to both sides:

x + 6 = 12 - 5x
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6x + 6 = 12

Now, we subtract 6 from each side, because, the opposite of addition, is subtraction:

6x + 6 = 12
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Now, divide by 6, on both sides:

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x + 6 = 17x

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x + 6 = 17x
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The answer is, 'B.'

I hope this helps!
8 0
3 years ago
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Finger [1]

Answer:

Classifications would include

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Those would be classifications

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Hi, i would love to help you but there is no graph below :(
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2 years ago
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Digiron [165]

Answer:

Hey There!

\huge\colorbox{yellow}{Myself \: someone}

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