She was at 500 ft most of the time.
You just divide 1,500 by 3 because she was at 1/3 of 1,500 altitude
75 is divisible by 3. It equals 25.
I hope this helped!!
1. By the Law of Sines, you have:
SinA/a=SinB/b=SinC/c
2. You don't need the fraction SinC/c, so you can eliminate it. Then:
SinA/a=SinB/b
A=40°
a=19
B=m∠b
b=13
3. When you substitute this values into SinA/a=SinB/b, you obtain:
SinA/a=SinB/b
Sin(40°)/19=SinB/13
SinB=13xSin(40°)/19
m∠b=SinB^-1(13xSin(40°)/19)
m∠b=26.1°
Therefore, the answer is: 26.1 degrees.
Answer:
-2/3
Step-by-step explanation:
Rise: 4
Run: -6
Slope = Rise over run
Slope = 4 / -6
4 / -6 = -2/3
The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.