Area of the base = 1/2 * 10 * 5sqrt3 = 25 sqrt3
Total surface area = 25 sqrt3 + 3 * 1/2 * 10 * slant height = 214.5
25 sqrt3 + 15h = 214.5
15h = 214.5 - 25 sqrt3
h = (214.5 - 25sqrt3() / 15
= 11.41 cm to nearest hundredth
Lets say the 3x3 Matrix is
M = [1 5 2 ]
[1 1 7 ]
[0 -3 7 ]
We apply the Gauss-Jordan elimination method
(Procedure and result shown in the image below)
Answer:
Nope
Step-by-step explanation:
Standard form for a linear equation in two variables is 
with the terms containing x and y on the left side of the equation and a number on the right side.
Subtract 3 from both sides.
Add 5y.
Answer:
5X + 8Y >= 300; intersection at (-20, 50)
Step-by-step explanation:
let t = work hours
0 < t < 30
X = time lawn mowing
Y = time babysitting.
X + Y < 30
5X + 8Y >= 300
We could solve...
X < 30 - Y
5(30 - Y) + 8Y >=300
150 - 5Y + 8Y >= 300
3Y >=150
Y >=50
then X < -20
intersection at (-20, 50)
Since 500 is the area, and 20 is the length, divide 500 by 20. Your answer is a decimal. (0.04) therefore, you have to make it into a whole number. So move the decimal to the right two times. So 4 is your height.
