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Thepotemich [5.8K]
3 years ago
14

Find two rational numbers such that the sum of the first and three times the second is 5 and the sum of second and two times the

first is 8.
A. (x,y) = (16/5,-2/5)
B. (x,y) = (-17/5,-2/5)
C. (x,y) = (-16/5,-2/5)
D. (x,y) = (19/5, 2/5)
E. (x,y) = (-19/5, 3/5)

Mathematics
1 answer:
masha68 [24]3 years ago
7 0

Answer: E. (x,y) = (-19/5, 3/5)

Step-by-step explanation:

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What are distinct angles?
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Distinct angles are when the angles of a polygon are all different.
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3 years ago
1 2 3 4 5 6 7 8 9 10 TIME REMAINING 52:51 Use the data set to determine which statements are correct. Check all that apply. 35,
Nady [450]

Answer:

The true statements are:

  • The median is 38.5.
  • There is an outlier.
  • The lower quartile is 29.
  • The upper quartile is 70.
  • The interquartile range is 41.

Step-by-step explanation:

The given data are:  35, 41, 18, 75, 36, 21, 62, 29, 154, 70

Make the data in order from the least to the greatest

18 , 21 , 29 , 35 , <u>36 , 41</u> , 62 , 70 , 75 , 154

So, the median of the data = (36 + 41)/2 = 38.5

We can deduce that The number 154 represents an outlier because the difference between 154 and 75 is much greater than the difference between the other data

If we divided the data to two groups , they will be:

(18 , 21 , <u>29 </u>, 35 , 36)  ,  (41 , 62 , <u>70 </u>, 75 , 154)

So, The lower quartile Q1 is the median of the first group = 29

And the upper quartile Q2 is the median of the second group = 70

And the interquartile range = Q2 - Q1 = 70 - 29 = 41

So, the true statements are:

  • The median is 38.5
  • There is an outlier
  • The lower quartile is 29
  • The upper quartile is 70
  • The interquartile range is 41.
7 0
3 years ago
I need the answer please
Yuri [45]

Answer:

D - All rational numbers are integers.

Step-by-step explanation:

This is because integers is a subcategory of rational numbers, so there are other rational numbers that aren't integers.

3 0
3 years ago
What the ratio form is
levacccp [35]
If i am not mistaken it is 4:12 but you can ask an expert to make sure
7 0
3 years ago
Read 2 more answers
A sample of radium has a weight of 1.5 mg and a half-life of approximately 6 years.
pogonyaev

Answer:

0.75 mg

Step-by-step explanation:

From the question given above the following data were obtained:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Amount remaining (N) =.?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Number of half-lives (n) =?

n = t / t₁/₂

n = 6/6

n = 1

Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Number of half-lives (n) = 1

Amount remaining (N) =.?

N = 1/2ⁿ × N₀

N = 1/2¹ × 1.5

N = 1/2 × 1.5

N = 0.5 × 1.5

N = 0.75 mg

Thus, 0.75 mg of the sample is remaining.

5 0
2 years ago
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