2x⁴+17x²+8
Let X = x² →→(x = + or -√X )
The quadratic becomes : 2.X² + 17.X + 8. Now solve for X:
X' = [-b+√(b²-4ac)]/2a and X" = [-b-√(b²-4ac)]/2a
Plug I the values of a, b and c and you will find;
X' = -1/2 and X" = - 8
Since X = √x → →X' = √( -1/2) [imaginary roots]
and X" = √-8 →→ X" = 2√-2 [imaginary roots]
Then:
1st ROOT: X' = - √1/2.i
2nd ROOT: X" = + √1/2.i
3rd ROOT: X" = + 2√2.i
4th ROOT: X" = - 2√2.i
Answer: the coordinates of B' are (6, -13)
Justification:
1) Translating triangle ABC according to the rule (x,y) → (x + 2, y - 8) means that every single point of the triangle will be translated two units to the righ (x + 2) and 8 units downward (y - 8).
2) To find the coordinates of anay image you have to add up 2 to the x coordinate (x + 2) and subtract 8 from the y-coordinate (y - 8).
3) Peforming those simple operations to the coordinates of the point B (4, -5), you will obtain the point B':
* x' = x + 2 = 4 + 2 = 6
* y' = y - 8 = -5 - 8 = - 13
Answer: the coordinates of B' are (6, -13)
Answer:
15
Step-by-step explanation:
