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IceJOKER [234]
3 years ago
15

How do you determine the volume of a regular object if you don't know the density?

Chemistry
1 answer:
Ann [662]3 years ago
4 0

Answer:

mol times or devided by molar volume

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(b) The chemical equation for the reaction between lithium and oxygen is 4Li + 0,2L1,0 Write a chemical equation for the reactio
BabaBlast [244]

Answer:

Li3N

Explanation:

Li+N2=Li3N.........................

5 0
3 years ago
Perform the following calculations. Express the answers with the correct number of significant figures.
11Alexandr11 [23.1K]
Since there are no conversions to be done just add them as is
a) 1 g
b) 1.0 kg
c) 22 L
d) 3.6 cm
<span>e) 104.9 g</span>
7 0
3 years ago
In ____________, particles change directly from a solid to a gas
goblinko [34]

Answer:

Sublimation.

Explanation:

Sublimation is the conversion between the solid and the gaseous phases of matter, with no intermediate liquid stage

8 0
3 years ago
BRAINLIEST AND 30 POINTS! concept map for four types of intermolecular forces and a certain type of bond is shown.
Sphinxa [80]

D represents ion-dipole forces that are stronger than the force C.

Explanation:

D represents the ion-dipole force.

C represents the H-bonding forces.

ion-dipole force is a force that is due to electrostatic attraction and has a dipole between an ion and a neutral molecule.

It is electrostatic in nature.

A hydrogen bond is the force between the hydrogen with the electro negative atom of one molecule, to electro negative atom of some other molecule. such as: O, F, N

Ion dipole force is stronger than the H-bonding.

3 0
3 years ago
It take 38.70cm³ of 1.90m NaoH to neutralize 10.30cm³ of H2so4 in a battery, calculate the molar concentration of H2so4
zlopas [31]

Answer:

M_{acid}=3.57M

Explanation:

Hello there!

In this case, since this acid-base neutralization is performed in a 1:2 mole ratio of acid to base as the former is a diprotic acid (two hydrogen ions in the molecule), we can write the following equation:

2M_{acid}V_{acid}=M_{base}V_{base}

In such a way, we can solve for the molarity of the acid, given the molarity and concentration of the NaOH base and the volume of the acid:

M_{acid}=\frac{M_{base}V_{base}}{2V_{acid}}

Thus, we plug in the given data to obtain:

M_{acid}=\frac{38.70cm^3*1.90M}{2(10.30cm^3)} \\\\M_{acid}=3.57M

Best regards!

8 0
3 years ago
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