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Aneli [31]
3 years ago
15

Convert 2.39 x 1022 molecules of water into moles of water

Chemistry
1 answer:
torisob [31]3 years ago
6 0

Answer:

0.0397\ \text{mol}

Explanation:

Number of molecules of water = 2.39\times 10^{22}

N_A = Avogadro's number = 6.022\times 10^{23}\ \text{mol}^{-1}

Number of moles is given by

\dfrac{2.39\times 10^{22}}{6.022\times 10^{23}}

=0.0397\ \text{mol}

The number of moles of water is 0.0397\ \text{mol}.

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lukranit [14]

Answer:

a=0.4\ m/s^2

Explanation:

1. Given that,

Initial speed of a bicycle, u = 4 m/s

The final speed of a bicycle, v = 6 m/s

Time, t = 6 s

We need to find the acceleration of the bicycle. We know that, acceleration is    equal to the change in speed divided by time taken. So,

a=\dfrac{v-u}{t}\\\\a=\dfrac{6-4}{5}\\\\a=0.4\ m/s^2

So, the acceleration of the bicycle is equal to 0.4\ m/s^2.

5 0
3 years ago
What is a common misconception about not following food regulations?
Dima020 [189]

Explanation:

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8 0
3 years ago
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Three factors affecting gas pressure are the amount of gas, temperature, and __________.
Olenka [21]
It's A. volume
Pressure = \frac{moles * const * temperature}{volume}
with const depends on the chosen unit of volume
I think so... 
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3 years ago
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8 l of water at 19 ∘c are mixed with 1.1 l of water at 47 ∘c in an insulated container. what is the final temperature of the sys
stepladder [879]
1692.9 is the answer


5 0
3 years ago
In an electroplating process, copper (ionic charge +2e, atomic weight 63.6 g/mol) is deposited using a current of 10.0 A. What m
salantis [7]

Answer : The mass of copper deposit is, 1.98 grams

Explanation :

First we have to calculate the charge.

Formula used : Q=I\times t

where,

Q = charge = ?

I = current = 10 A

t = time = 10 min = 600 sec      (1 min = 60 sec)

Now put all the given values in this formula, we get

Q=10A\times 600s=6000C

Now we have to calculate the number of atoms deposited.

As, 1 atom require charge to deposited = 2\times (1.6\times 10^{-19})  

Number of atoms deposited = \frac{(6000)}{2\times(1.6\times 10^{-19})}=1.875\times 10^{22} atoms

Now we have to calculate the number of moles deposited.

Number of moles deposited = \frac{(1.875\times 10^{22})}{(6.022\times 10^{23})}=0.03113 moles

Now we have to calculate the mass of copper deposited.

1 mole of Copper has mass = 63.5 g  

Mass of Copper Deposited = 63.5\times 0.03113 =1.98g

Therefore, the mass of copper deposit is, 1.98 grams

5 0
3 years ago
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