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2 years ago

What does it mean to tare a balance and why do you think it is important to complete this before you begin measuring mass?

Chemistry

2 answers:

aev [14]2 years ago

6 0

Answer:

allows for you to account for only the weight of the substance being measured and not the vessel it’s being measured in.

Explanation:

What does it mean to tare a balance and why do you think it is important to complete this before you begin measuring mass? Explanation: The term tare is used when weighing chemicals on a balance, using the tare button allows for you to account for only the weight of the substance being measured and not the vessel it’s being measured in.

alexgriva [62]2 years ago

6 0

Explanation:

Explanation: The term tare is used when weighing chemicals on a balance, using the tare button allows for you to account for only the weight of the substance being measured and not the vessel it's being measured in.

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3 years ago

The pyrolysis of ethane proceeds with an activation energy of about 300 kJ/mol. How much faster is the decomposition at 625°C th

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Answer:

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_2$ = rate of reaction at $T_2$

$K_1$ = rate of reaction at $T_1$

$Ea$ = activation energy of the reaction

R = gas constant = 8.314 J/K mol

$E_a=300 kJ/mol=300,000 J/mol$

$T_2=625^oC=898.15 K,T_1=525^oC=798.15 K$

$\log (\frac{K_2}{K_1})=\frac{300,000 J/mol}{2.303\times 8.314 J/K mol}[\frac{1}{798.15 K}-\frac{1}{898.15 K}]$

$\log (\frac{K_2}{K_1})=2.185666$

$K_2=153.344\times K_1$

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

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