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BARSIC [14]
3 years ago
7

Compare strontium with rubidium in terms of the following properties:

Chemistry
1 answer:
Ilya [14]3 years ago
6 0

Answer:

Strontium is smaller

Strontium has the higher ionization energy

Strontium has more valence electrons

Explanation:

It must be understood that both elements belong to the same period i.e the same horizontal band of the periodic table

While Rubidium is an alkali metal(group 1) while Strontium is an alkali earth metal(group 2)

Since they are in the same period, periodic trends would be useful in evaluating their properties

In terms of atomic radius, rubidium is larger meaning it has a bigger atomic size

Generally, across the periodic table, atomic radius is expected to decrease and thus Rubidium which is leftmost is expected to have the higher atomic radius

Since strontium belongs to group 2 of the periodic table, it has 2 valence electrons which is more than the single valence electron that rubidium which is in group 1 has

In terms of ionization energy, the atom with the higher number of valence electrons will have the higher ionization energy which is strontium in this case

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Which group or groups of atoms are the only atoms with f orbitals A. All atoms heavier than barium B. All atoms heavier than kry
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Answer:

All atoms heavier than barium

Explanation:

In the periodic table, elements are divided into blocks. We have the;

s- block elements

p- block elements

d- block elements

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However, immediately after Barium, we now encounter elements that have f-orbitals. Barium possesses a fully filled d-orbital. Hence after it, we see elements with 4f and 5f orbitals called the Lanthanides and actinides. The elements following the lanthanide and actinide series possess completely filled f-orbitals as inner orbitals.

Hence elements heavier than barium all possess f-orbitals.

6 0
3 years ago
If object A is placed on the pH scale at pH = 3 and object B is placed at pH = 8, which of the following must not be true?
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4 0
2 years ago
Someone answer this please...
boyakko [2]

Answer:

120 mol Mg

General Formulas and Concepts:

<u>Chemistry - Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

120 moles H₂

<u>Step 2: Identify Conversions</u>

RxN:   3 mol H₂ = 3 mol Mg

<u>Step 3: Stoichiometry</u>

<u />120 \ mol \ H_2(\frac{3 \ mol \ Mg}{3 \ mol \ H_2} ) = 120 mol Mg

7 0
3 years ago
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