1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BARSIC [14]
3 years ago
7

Compare strontium with rubidium in terms of the following properties:

Chemistry
1 answer:
Ilya [14]3 years ago
6 0

Answer:

Strontium is smaller

Strontium has the higher ionization energy

Strontium has more valence electrons

Explanation:

It must be understood that both elements belong to the same period i.e the same horizontal band of the periodic table

While Rubidium is an alkali metal(group 1) while Strontium is an alkali earth metal(group 2)

Since they are in the same period, periodic trends would be useful in evaluating their properties

In terms of atomic radius, rubidium is larger meaning it has a bigger atomic size

Generally, across the periodic table, atomic radius is expected to decrease and thus Rubidium which is leftmost is expected to have the higher atomic radius

Since strontium belongs to group 2 of the periodic table, it has 2 valence electrons which is more than the single valence electron that rubidium which is in group 1 has

In terms of ionization energy, the atom with the higher number of valence electrons will have the higher ionization energy which is strontium in this case

You might be interested in
NH3 1. Lewis Structure 2. Perspective drawing 3. Number of atoms bonded to central atom 4. Number of non-bonding electron pairs
Stels [109]

This question will be answered in parts:

<h3><u>1. Lewis Structure</u></h3>

There are three N-H bonds and one lone pair on the nitrogen atom in the Lewis structure of NH3. On hydrogen atoms, there are no lone pairs that can only hold two electrons.

The lewis structure is as shown in the diagram.

<h3><u>2. Perspective Drawing</u></h3>

A molecule is shown from a viewpoint with its atoms' bonds pointing either in your direction (bolded wedge) or away from you (hash wedge).

The perspective drawing of NH3 is given here

<h3><u>3.Number of atoms bonded to central atom </u></h3>

Nitrogen is the central atom in the Lewis structure of NH3, which also contains one lone pair and is bound to the three hydrogen atoms.

<h3><u>4.Number of non-bonding electron pairs on the central atom</u></h3>

Three bond pairs and two lone pairings exist. This is due to the fact that nitrogen contains five electrons in its outer shell, three of which are bound to hydrogen atoms and two of which are free.

<h3><u>5. Electronic geometry:</u></h3>

The electronic geometry of nitrogen is based on a tetrahedral arrangement of electron pairs, and ammonia likewise possesses four electron pairs. There is only one lone pair because there are only three connected groupings. But since the lone pairs are "invisible," the ammonia has a pyramidal form.

<h3><u>6. Molecular geometry with ideal bond angles</u></h3>

The molecular geometry of ammonia it has a trigonal pyramidal or distorted tetrahedral structure.

The bond angle in ammonia is less than the standard 109.5⁰. The bond angle is 107⁰

<h3><u>7.Hybridization of central atom</u></h3>

The core nitrogen (N) atom in the NH3 molecule has a steric number of (3 + 1) = 4, which causes Sp3 hybridization.

<h3><u>8. Polarity:</u></h3>

Because of its asymmetrical form, a trigonal pyramidal structure, and the different electronegativities of N(3.04) and H(2.2), the NH3 (ammonia) molecule is polar in nature .

To know more about ammonia, you can refer to:

brainly.com/question/13960908

#SPJ4

3 0
1 year ago
To make 2.00 L of 0.300 M sulfuric acid, how many mL of a 1.00 M stock solution should be used?
Tamiku [17]
We are given with
M1 = 1.00 M

M2 = 0.300 M
V2 = 2.00 L

We are asked to get V1

Using material balance
M1 V1 = M2 V2
Substituting the given values
1.00 V1 = 0.300 M (2.00 L)
V1 = 0.600 L or 600 mL
THe volume needed is 600 mL<span />
3 0
3 years ago
How many moles of oxygen are required to produce 37.15 g CO2?
denpristay [2]
Carbon = 12.010. Oxygen = 15.999 x 2 15.999 x 2 = 31.998 + 12.010 = 44.008 \frac{37.15 grams * 1 mole CO2}{44.008 grams}
8 0
3 years ago
Read 2 more answers
What is meant by localised orbitals? Explain.
Anni [7]
Localized molecular orbitals are molecular orbitals which are concentrated in a limited spatial region of a molecule, for example a specific bond or a lone lake on a specific atom.
5 0
3 years ago
How do the equilibrium concentrations of the reactants compare to the equilibrium concentrations of the product?
Scorpion4ik [409]

Answer: It depends equilibrium constant K

Explanation:   You need to to have reaction formula.

If K >> 1 then concentrations of products are much bigger than

concentrations of reactants. If K < < 1, concentration of products is small.

6 0
3 years ago
Other questions:
  • Which organ is a part of circulatory system? <br> a. brain<br> b. heart<br> c. lungs<br> d. stomach
    14·2 answers
  • Write the Lewis structure and molecular formula for each of the following hydrocarbons:
    6·1 answer
  • What is this number in standard notation, 8.2x10^2
    11·1 answer
  • A soild reactant is placed in to a beaker of warm water. The liquid vigorously bubbles as the solid dissolves into the solution.
    7·1 answer
  • What does 2,3-dibromopentane look like?
    13·1 answer
  • Whats a covalent bond ?
    13·2 answers
  • How does a car safely transfer the kinetic energy of the passenger and the car?
    15·1 answer
  • What type of molecule is being modeled?
    12·2 answers
  • Calculate the Molarity when 14.6 g Ethanol (C2H5OH) is dissolved in a 2.10 L solution.
    12·1 answer
  • 5. For the equilibrium
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!