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4 years ago

Compare strontium with rubidium in terms of the following properties:

Chemistry

1 answer:

Ilya [14]4 years ago

6 0

Answer:

Strontium is smaller

Strontium has the higher ionization energy

Strontium has more valence electrons

Explanation:

It must be understood that both elements belong to the same period i.e the same horizontal band of the periodic table

While Rubidium is an alkali metal(group 1) while Strontium is an alkali earth metal(group 2)

Since they are in the same period, periodic trends would be useful in evaluating their properties

In terms of atomic radius, rubidium is larger meaning it has a bigger atomic size

Generally, across the periodic table, atomic radius is expected to decrease and thus Rubidium which is leftmost is expected to have the higher atomic radius

Since strontium belongs to group 2 of the periodic table, it has 2 valence electrons which is more than the single valence electron that rubidium which is in group 1 has

In terms of ionization energy, the atom with the higher number of valence electrons will have the higher ionization energy which is strontium in this case

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julsineya [31]

A binary compound is ionic, therefore it could not be A. The answer is aluminium fluoride (D). <span />

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4 years ago

Calculate the molarity of a 23.55-ml solution which contains 28.24 mg of sodium sulfate (used in dyeing and printing textiles, =

Verizon [17]

The first thing to do is to convert the mass of sodium sulfate to moles. Since the given is in milligrams convert it to grams which would be 0.02824 grams. The number of moles can be calculated by dividing the converted weight with the given molar mass which is 139.04 g/mol. The number of mols in the solution is 2.03x10^-4 mols. Then divide the number of moles with 0.02355 L. The molarity of the solution is 0.00862 M.

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4 years ago

Solid mixture of one or more minerals and organic matter

Alborosie

Answer:

Rock

Explanation:

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3 0

3 years ago

Calculate the value of ΔG∘rxnΔGrxn∘ for the following reaction at 296 K. Ka = 2.9 × 10–8 and assume Ka does not change significa

oee [108]

Answer:

$\Delta G_{rxn}=42.7\frac{kJ}{mol}$

Explanation:

In this case, for the dissociation of hypochlorous acid, we know that the acid dissociation constant (Ka) is 2.9x10⁻⁸, which is related with the Gibbs free energy as shown below:

$\Delta G_{rxn}=-RTln(K)$

But in this case K is just Ka, therefore, at 296 K, it turns out:

$\Delta G_{rxn}=-8.314\frac{J}{mol*K}*296K*ln(2.9x10^{-8})\\\\\Delta G_{rxn}=42.7\frac{kJ}{mol}$

Such result, means that the reaction is nonspontaneous at the given temperature, it means it is not favorable (not easily occurring).

Best regards.

7 0

3 years ago

For the reaction 2H2 + O2 --> 2H2O, how many grams of oxygen are needed to react 3 moles of hydrogen?

mr Goodwill [35]

Answer:

48 grams

Explanation:

The chemical equation for the reaction is the following:

2 H₂ + O₂ → 2 H₂O

That means that 2 moles of H₂ react with 1 mol of O₂ to produce 2 moles of H₂O. We convert the moles of oxygen (O₂) by using the molecular weight (MW) as follows:

MW(O₂) = 16 g/mol x 2 = 32 g/mol

mass of O₂ = 1 mol x 32 g/mol = 32 g

So, we have the following stoichiometric ratio: 32 g O₂/2 moles H₂. We have 3 moles of hydrogen (H₂), so we multiply the moles by the stoichiometric ratio to calculate how many grams are needed:

3 moles H₂ x 32 g O₂/2 moles H₂ = 48 g O₂

<em>Therefore, 48 grams of O₂ are needed to react with 3 moles of H₂.</em>

4 0

3 years ago