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Anastaziya [24]
3 years ago
6

The conjugation of the trans/cis product is likely diminished due to steric interactions between the cis-phenyl and the nearby v

inyl hydrogen. This interaction likely causes the phenyl ring to twist out of the plane, and thus no longer to be fully conjugated with the adjacent double bond. The trans-trans isomer has no such steric interactions, and thus it is expected to be more fully conjugated. The two isomers are thus may have different light absorbing properties.
Considering all this, which product stereoisomer do you expect to have the highest lambda max value in the UV-V is spectrum- the trans/trans or the cis/trans? Briefly explain your answer.
Chemistry
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

The trans/trans stereoisomer.

Explanation:

So, we are going to have two stereoisomers or arrangements for this chemical compound, that is the Cis/trans, the trans/trans.

For a compound to be seen with UV, the main or primary condition is conjugation or how conjugated the chemical specie or compound is.

Thus, the more the conjugation, the more or the higher the wavelength or lands value.

=> The Trans/trans stereoisomer will have the highest lamda value or wavelength because the energy gap in its π - π* Transitioning deceases due to the STERIC interactions, and the more the decrease in the energy gap, the more or the higher the lamda value or wavelength.

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The teal line of the hydrogen emission spectrum has a wavelength of 486.0 nm. A hydrogen emission spectrum has a violet, a blue,
Sloan [31]

Answer:

The correct answer to the following question will be "4.08 × 10⁻¹⁹ Joule".

Explanation:

Given:

Wavelength, λ = 486.0 nm

As we know,

E=h\upsilon =\frac{hc}{\lambda}

On putting the estimated values, we get

⇒          =\frac{1241.5 \ ev\ nm}{486 \ nm}

⇒          =2.554 \ ev

∴ 1 ev = 1.6 × 10⁻¹⁹ J

Now,

Energy, E=2.554\times 1.6\times 10^{-19}

⇒               =4.08\times 10^{-19} Joule

7 0
3 years ago
A 34.53 ml sample of a solution of sulfuric acid, h2s04, reacts with 27.86 ml of 0.08964 m naoh solution. calculate the molarity
Gnoma [55]
The balanced equation between NaOH and H₂SO₄ is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of moles of NaOH moles reacted = molarity of NaOH x volume
number of NaOH moles = 0.08964 mol/L x 27.86 x 10⁻³ L = 2.497 x 10⁻³ mol
according to molar ratio of 2:1
2 mol of NaOH reacts with 1 mol of H₂SO₄
therefore 2.497 x 10⁻³ mol of NaOH reacts with - 1/2 x 2.497 x 10⁻³ mol of H₂SO₄
number of moles of H₂SO₄ reacted - 1.249 x 10⁻³ mol 
Number of H₂SO₄ moles in 34.53 mL - 1.249 x 10⁻³ mol 
number of H₂SO₄ moles in 1000 mL - 1.249 x 10⁻³ mol / 34.53 x 10⁻³ L = 0.03617 mol 
molarity of H₂SO₄ is 0.03617 M
6 0
3 years ago
A chemist combines iodoethane (ch3ch2i with sodium hydroxide (naoh in an aqueous solution at 100°c. which change to the reaction
antoniya [11.8K]

The replacing of sodium hydroxide with potassium hydroxide (KOH) to the reaction will least affect the organic product that forms.

 

Potassium hydroxide is an inorganic compound with the formula KOH, and is commonly called caustic potash. Along with sodium hydroxide, this colorless solid is a prototypical strong base.

4 0
3 years ago
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Are there any parts of the human body that get oxygen directly from the air and not from the blood?
n200080 [17]

Answer: Cornea  

Explanation: The cornea is the only part of a human body that has no blood supply as it gets oxygen directly through the air.

3 0
3 years ago
Sugar is a covalently linked compound with many atoms. Water is able to dissolve sugar. What does this suggest about the atoms o
luda_lava [24]

Answer:

When you put sugar inside of a cup with water, the sugar is still visible because it's molecules have just gotten in touch with water molecules. The sugar molecules are still attracted to each other but as you stir it, it seems to disappear but not completely. When the water is stirred sugar mix with water and water molecules place themselves between the sugar ones.

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