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3 years ago

How many moles of carbon atoms are present in 5.4 moles of glucose? Answer in units of mol.

Chemistry

1 answer:

Delvig [45]3 years ago

3 0

Answer:

32.4 mol

Explanation:

Given data:

Number of moles of C atom present = ?

Number of moles of glucose = 5.4 mol

Solution:

Glucose formula = C₆H₁₂O₆

There are 6 moles of C atoms are present in one mole of glucose.

In 5.4 moles of glucose:

5.4 mol × 6 = 32.4 mol

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Answer:

Explanation:

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Zepler [3.9K]

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2 years ago

If each NADHNADH generates 3 ATPATP molecules and each FADH2FADH2 generates 2 ATPATP molecules, calculate the number of ATPATP m

Nadusha1986 [10]

Answer:

$128~ATP$

Explanation:

The metabolic pathway by which energy can be obtained from a fatty acid is called "beta-oxidation". In this route, acetyl-Coa is produced by removing 2 carbons from the fatty acid for each acetyl-Coa produced. In other words, for each round, 1 acetyl Coa is produced and for each round 2 carbons are removed from the initial fatty acid. Therefore, the first step is to calculate the number of rounds that will take place for an 18-carbon fatty acid using the following equation:

$Number~of~Rounds=\frac{n}{2}-1$

Where "n" is the number of carbons, in this case "18", so:

$Number~of~Rounds=\frac{18}{2}-1~=~8$

We also have to calculate the amount of Acetyl-Coa produced:

$Number~of~Acetyl-Coa=\frac{18}{2}~=~9$

Now, we have to keep in mind that in each round in the beta-oxidation we will have the production of 1 $FADH_2$ and 1 $NADH$ . So, if we have 8 rounds we will have 8 $FADH_2$ and 8 $NADH$ .

Finally, for the total calculation of ATP. We have to remember the yield for each compound:

-) $1~FADH_2~=~2~ATP$

-) $1~NADH~=~3~ATP$

-) $Acetyl~CoA~=~10~ATP$

Now we can do the total calculation:

$(8*2)~+~(8*3)~+~(9*10)=130~ATP$

We have to subtract "2 ATP" molecules that correspond to the activation of the fatty acid, so:

$130-2=128~ATP$

In total, we will have 128 ATP.

I hope it helps!

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3 years ago

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Charra [1.4K]

Answer:

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2 years ago

How do you know if a reaction is endothermic?

Vikentia [17]

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3 years ago