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Sever21 [200]
3 years ago
13

How many moles of carbon atoms are present in 5.4 moles of glucose? Answer in units of mol.

Chemistry
1 answer:
Delvig [45]3 years ago
3 0

Answer:

32.4 mol

Explanation:

Given data:

Number of moles of C atom present = ?

Number of moles of glucose = 5.4 mol

Solution:

Glucose formula = C₆H₁₂O₆

There are 6 moles of C atoms are present in one mole of glucose.

In 5.4 moles of glucose:

5.4 mol × 6 = 32.4 mol

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135 Joules of heat are required to increase the temperature of 10.0 grams of an unknown metal from 25.0∘C to 40.0∘C:
Sever21 [200]

Answer:

270 Joules

Explanation:

The specific heat capacity equation will be used for this question i.e.

Q = m. c. ΔT

Where; Q = Amount of heat

m = mass of substance

C = specific heat capacity of

substance

ΔT = change in temperature

(Final temp - initial temp)

However, for this unknown metal, we need to find the specific heat first by saying; C = Q / mΔT

Q= 135J, C=?, m= 10g, ΔT = (40-25 = 15°C)

C = 135 / 15 × 10

C = 135/150

C = 0.9 J/g°C

If the specific heat capacity of the unknown metal is 0.9 J/g°C, then at a mass of 20.0g, and a ΔT of 15°C, the amount of heat needed is:

Q = m. c. ΔT

Q = 20 × 0.9 × (40-25)

Q = 18 × 15

Q = 270J

270 Joules of heat is needed to increase the temperature of 20g of the metal from 25 - 40°C

8 0
3 years ago
What is the strength of alloys and what is the solubility of alloys?
il63 [147K]

Answer:

The most common reason for alloying is to increase the strength of a metal. This requires that barriers to slip be distributed uniformly throughout the crystalline grains. On the finest scale, this is done by dissolving alloying agents in the metal matrix (a procedure known as solid solution hardening

Explanation:

hey why u search i have book that answer i got mark as brainlist please okkkkkk

3 0
3 years ago
Calculate the food energy (joules/
Anna007 [38]

Calculate the food energy (joules/g) of one of your food samples. one chemistry calorie is equal to 4.186 joules. convert the energy you calculated to kilojoules (1 kj = 1000 j). since nothing is given, an example is avocadoes have 160 cal/100 g serving

(160 cal/ 100 g)(4.186 J/ 1 cal) (1 kJ/1000 J) = 0.0067 kJ/g

5 0
3 years ago
Suppose that coal of density 1.5 g/cm^3 is pure carbon. (It is, in fact, much more complicated, but this is a reasonable first a
NISA [10]

Answer:

q = -6464.9 kJ

Explanation:

We are given that the heat of combustion is  ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.

vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³

m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g

mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol

q =  −394 kJ /mol C x 16.41 mol C = -6464.9 kJ

7 0
3 years ago
How many protons does the largest transition metal have in its nucleus?
CaHeK987 [17]
The largest transition metal is copernicium with 112 protons
4 0
3 years ago
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