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irina [24]
2 years ago
14

Who was the first person to show strong empirical evidence for the existence of atoms?.

Chemistry
1 answer:
Mekhanik [1.2K]2 years ago
6 0

Given what we know, we can confirm that John Dalton was the first person to show strong empirical evidence for the existence of atoms.

<h3>Who was John Dalton?</h3>
  • He was a renowned scientist with knowledge in many fields.
  • He was known to be a chemist, meteorologist, and physicist.
  • He proposed the atomic theory and carried out experiments to provide supporting evidence.

Therefore, given his proposal of the atomic theory and the experiments he carried out to provide evidence to support his claims, we can confirm that John Dalton was the first person to show strong empirical evidence for the existence of atoms.

To learn more about atoms visit:

brainly.com/question/13981855?referrer=searchResults

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Write a balanced overall reaction from these unbalanced half-reactions sn and ag
loris [4]
Balance each one by adding electrons to make the charges on both sides the same:

Sn--> Sn2+ + 2 e-
Ag+ + 1 e- --> Ag

Now, you have to have the same number of electrons in the two half-reactions, so multiply the second one by 2 to get:

2 Ag+ + 2 e- --> 2 Ag

Now, just add the two half reactions together, cancelling anything that's the same on both sides:

2 Ag+ + Sn --> Sn2+ + 2 Ag

And you're done.
8 0
3 years ago
Who was the first person to discover the existence of electrons​
k0ka [10]
Electron was discovered by J. J. Thomson in 1897 when he was studying the properties of cathode ray.
4 0
3 years ago
Read 2 more answers
The Lewis diagram for BH2 is:
Luda [366]

Answer:

Electron pair geometry- trigonal planar

There is one lone pair around the boron atom

The geometry of BH2 is bent

Explanation:

The valence shell electron pair repulsion theory offers a frame work for determining the shape of molecules based on the number of electron pairs of the valence shell of the central atom in the molecule.

In BH2-, the central atom is boron. There is a lone pair on boron. Owing to the lone pair on boron, the molecular geometry of BH2 is bent.

4 0
3 years ago
The volume of a gas is 550 mL at 960 mm Hg and 200.0 C. What volume
Masja [62]

Answer:

The volume will be 568.89 mL.

Explanation:

Boyle's law says that "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or P * V = k

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. That is, the pressure of the gas is directly proportional to its temperature. Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T}=k

Where P = pressure, T = temperature, K = Constant

Finally, Charles's law indicates that as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

\frac{V}{T}=k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{P*V}{T} =k

Studying an initial state 1 and a final state 2, it is fulfilled:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

In this case:

  • P1= 960 mmHg
  • V1= 550 mL
  • T1= 200 C= 473 K (being 0 C=273 K)
  • P2= 830 mmHg
  • V2= ?
  • T2= 150 C= 423 K

Replacing:

\frac{960 mmHg*550 mL}{473K} =\frac{830 mmHg*V2}{423 K}

Solving:

V2=\frac{423 K}{830 mmHg} *\frac{960 mmHg*550 mL}{473K}

V2= 568.9 mL

<u><em>The volume will be 568.89 mL.</em></u>

4 0
3 years ago
7.457kCal, convert to KJ<br> [18] = 4.184kCan]
777dan777 [17]

Answer:

can i see a image please

Explanation:

6 0
3 years ago
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