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4 years ago

4) Circle which statement(s) are TRUE: 4a. 3 x 42 = 3 x 16 4b. 35 = 53 4c. 25 = 10

1 answer:

3 0

A = false, it is simply not possible
B = false, it is also not possible
C = false, so it is also impossible

Am I missing anything? If not, I guess just don’t circle any of them!

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Round 81065 to the nearest ten thousand, hundred, ten, and thousand

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Ten thousand-80000
hundred-81100
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3 years ago

How much greater is the area of a a square with a side length of 8 inches than the area of a circle with radius of 4 inches?

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Area of a square= l²
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3 years ago

If x = 6, then what is y in this equation

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3 years ago

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2 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

4 years ago