Figure ABCD is transformed to figure A′B′C′D′:
1 answer:
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Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,
Here, ,Perpendicular AB = 4000
Solving for BC, we get,
(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
Answer:
Perimeter of the ΔDEF = 10.6 cm
Step-by-step explanation:
The given question is incomplete; here is the complete question with attachment enclosed with the answer.
D, E, and F are the midpoints of the sides AB, BC, and CA respectively. If AB = 8 cm, BC = 7.2 cm and AC = 6 cm, then find the perimeter of ΔDEF.
By the midpoint theorem of the triangle,
Since D, E, F are the midpoints of the sides AB, BC and CA respectively.
Therefore, DF ║ BC and
FD =
= 3.6
Similarly,
FE = 4 cm
And
DE =
= 3 cm
Now perimeter of ΔDEF = DE + EF + FD
= 3 + 4+ 3.6
= 10.6 cm
Perimeter of the ΔDEF is 10.6 cm.
