Answer:
Explanation:
The magnitude of the force of a moving cahrge, in our case a proton, trought a magentic field is given by:
(1)
where:
q is the proton charge (
)
v is the proton velocity (
)
B is the magnetic field (B = 1.17 T)
Now, we just need to solve the equaton (1) for \theta.

But the force F = ma, then:
m is the mass of proton (
)
a is the acceleration (
)

I hope it helps you!
Answer:
Explanation:
Let the force required be F . It is applied at the top of the box . The box is likely to turn about a corner . Torque of this force about this corner
= F x 2
This torque will try to turn the box . On the other hand the weight which is acting at CM will create a torque about the same corner . This torque will try to prevent the box to turn around the corner.
This torque of weight
= 100 x 1
= 100 pound ft.
For equilibrium
Torque of F = torque of weight.
F x 2 = 100
F = 50 pounds .
Answer:
A parallel circuit has two or more paths for current to flow through.
Voltage is the same across each component of the parallel circuit.
The sum of the currents through each path is equal to the total current that flows from the source.
Explanation:
The electrical charge is neutral. I hope this helps!
The car traverses a distance
after time
according to

where
is its acceleration, 10 m/s^2. The time it takes for the car to travel 25 m is

5 is pretty close to 4, so we can approximate the square root of 5 by 2. Then the car's velocity
after 2 s of travel is given by

which makes C the most likely answer.