Answer:
From liquid to solid or to solid or liquid the transition has to cross the grey zone.
Explanation:
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<h3>a. The impulse</h3>
The impulse is 100.0 Ns
The impulse I = Ft where
- F =average force = 50.0 N and
- t = time = 2.0 s
Substituting these values into the equation, we have
I = Ft
I = 50.0 N × 2.0 s
I = 100.0 Ns
The impulse is 100.0 Ns
<h3>b. Change in momentum</h3>
The change in momentum is 100 kgm/s
Since change in momentum Δp = I where I = impulse.
Since I = 100.0 Ns,
Substituting this into the equation, we have
Δp = I
= 100.0 Ns
= 100 kgm/s
The change in momentum is 100 kgm/s
<h3>c. Mass's change in velocity</h3>
The change in velocity is 25.0 m/s
Since change in momentum Δp = mΔv where
- m = mass = 4.0 kg and
- Δv = change in velocity.
Making Δv subject of the formula, we have
Δv = Δp/m
Substituting the values of the variables into the equation, we have
Δv = Δp/m
Δv = 100.0 kgm/s/4.0 kg
Δv = 25.0 m/s
The change in velocity is 25.0 m/s
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Heat conduction, also named as thermal conduction, is the heat flux in a body due to temperature difference and occurs by the movement of electrons within a body.
When all the available energies such as electrical energies, chemical energies or the nuclear energies are converted to the thermal energy, the the conversion process is called heat generation.
Thermal conduction is the process when the heat transfers from hotter region to the colder region.
In heat conduction analysis, the conversion of electrical, chemical or nuclear energy into thermal energy in solids is called as heat generation.
To know more about thermal conduction,
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Answer:
The total rate at which electrical energy is dissipated by the two resistors is 48 W.
The given parameters;
First resistor, R₁ = 25 ohm
Second resistor, R₂ = 15 ohm
power dissipated in the first resistor, P₁ = 36 W
In series circuit arrangement, the current flowing in each resistor is the same.
The current flowing in the first resistor is calculated as follows;
P = I²R₁
The equivalent resistance of the series arrangement is calculated as;
R = R₁ + R₂
R = 25 + 15
R = 40 ohms
The total rate at which electrical energy is dissipated by the two resistors;
P = I²R
P = 1.2(40)
P = 48 W
Thus, the total rate at which electrical energy is dissipated by the two resistors is 48 W.
Explanation: