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9966 [12]
3 years ago
15

If earth did not rotate how would air at the equator move?

Physics
2 answers:
Vlada [557]3 years ago
8 0

Answer: Option (a) is the correct answer.

Explanation:

If Earth did not rotate then the side of Earth which is nearer to the Sun will be the warmest. As a result, there will be presence of more warm air.

This air will then rise and move towards the poles, that is, colder regions which are far away from Sun.

Thus, we can conclude that if earth did not rotate then air would rise and move toward the poles at the equator.

Dmitry_Shevchenko [17]3 years ago
3 0
Heat rises, and it is warmer at the equator, so I think warm air would rise at the equator and move towards the cooler poles.
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Si tu velocidad al caminar es 0,3 m/s. Determina el tiempo que demorarias en llegar al sol en horas (REALIZAR TRANSFORMACIÓN DE
Contact [7]

Answer:

138,516,546.9 horas.

Explanation:

Tenemos que usar la ecuación:

Velocidad = distancia/tiempo

Acá tenemos:

Velocidad = 0.3m/s

distancia = 149597870700 m

y queremos resolver la ecuación para el tiempo:

0.3m/s =  149597870700m/tiempo.

tiempo =  149597870700m/(0.3m/s) = 498,659,569,000 s

y sabemos que una hora tiene 3600 segundos, entonces si queremos transformar de segundos a horas tenemos:

498,659,569,000 s = (498,659,569,000/3600) h = 138,516,546.9 horas.

6 0
3 years ago
At constant volume, the heat of combustion of a particular compound is − 3550.0 kJ / mol. When 1.075 g of this compound ( molar
swat32

Answer:

C=1,25\cdot 10^{5} kJ/^{\circ}C

Explanation:

First of all let's define the specific molar heat capacity.

C = \frac{-Q}{n\cdot \Delta T} (1)

Where:

Q is the released heat by the system

n is the number of moles

ΔT is the difference of temperature of the system  

Now, we can find n with the molar mass (M) the mass of the compound (m).

n=\frac{m}{M}=6.95\cdot 10^{-3} moles      

Using (1) we have:

C=\frac{-3550}{6.95\cdot 10^{-3} 4.073}

C=1,25\cdot 10^{5} kJ/^{\circ}C

I hope it helps!

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3 years ago
What are compounds considered to be
bija089 [108]

Answer:A compound is a substance formed when two or more elements are chemically joined.

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3 years ago
a force vector f has a magnitude of 12.0 n. it is oriented 60° to the left of the y ax what are its x and y components?
Arte-miy333 [17]

The  force vector that has a magnitude of 12.0 N. and is oriented 60° to the left of the (y) has the followings components:

  • v(x) =6 N
  • v(y) = 10.39 N

To solve this exercise the formulas and procedures we will use are:

  • v(x) = v * cosine (angle)
  • v(y) = v * sine (angle).

Where:

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  • v(x) = component of the vector on the (x) axis
  • v(y) = component of the vector on the (y) axis
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Information about the problem:

  • angle = 60º
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  • v(y)= ?

Applying the formula of the component of the vector in the (x) axis we have:

v(x) = v * cosine (angle).

v(x) = 12.0 N * cosine (60º)

v(x) =6 N

Applying the formula of the component of the vector in the (y) axis we have:

v(y) = v * sine (angle)

v(y) = 12.0 N * sine (60º)

v(y) = 10.39 N

<h3>What is a vector?</h3>

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