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9966 [12]
4 years ago
15

If earth did not rotate how would air at the equator move?

Physics
2 answers:
Vlada [557]4 years ago
8 0

Answer: Option (a) is the correct answer.

Explanation:

If Earth did not rotate then the side of Earth which is nearer to the Sun will be the warmest. As a result, there will be presence of more warm air.

This air will then rise and move towards the poles, that is, colder regions which are far away from Sun.

Thus, we can conclude that if earth did not rotate then air would rise and move toward the poles at the equator.

Dmitry_Shevchenko [17]4 years ago
3 0
Heat rises, and it is warmer at the equator, so I think warm air would rise at the equator and move towards the cooler poles.
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It takes 120 minutes for a man to ride his bicycle up the road to Alpe d'Huez in France. The vertical height of the climb is 1,1
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First solve the potential energy of the biker. using the fomula:
PE = mgh
where m  is the mass of the object
g is the acceleration due to gravity ( 9.81 m/s2)
h is the height

PE = 96 kg ( 1120 m ) ( 9.81 m/s2)
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then power = Work / time
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4 years ago
Particles q1, q2, and q3 are in a straight line. Particles q1 = -28.1 μC, q2 = +25.5 μC, and q3 = -47.9 μC. Particles q1 and q2
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3 years ago
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Control of air–fuel ratio

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3 years ago
A pulley system has an efficiency of 87.5 percent.
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work done on desk = m g h = 105 * 9.81 * 2.46 = 2534 Joules

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that is your 648 times distance your hand moved holding the rope

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2 years ago
A girl coasts down a hill on a sled, reaching level ground at the bottom with a speed of 7.1 m/s. The coefficient of kinetic fri
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The weight of the sled and girl is considered as the sum of the frictional force and weight

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\frac{1}{2}mv^2=\mu Nd\\\Rightarrow \frac{1}{2}\frac{783}{9.81}\times 7.1^2=0.045\times 783\times d\\\Rightarrow d=\frac{1}{2}\times \frac{783\times 7.1^2}{9.81\times 0.045\times 783}\\\Rightarrow d=114.19186\ m

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3 years ago
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